2 years ago

Tentukan himpunan penyelesaian dari persamaan linear berikut .

Mathematics

1 answer:

Andreas93 [3]2 years ago

3 0

A. Hope this helped im sorry if its wrong

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Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

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3 years ago

How would you come up with 2.5 from 2 1/2 hours in fraction and how would you come up with 4.5 from 414 in hours and fractions

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The clock breaks down to a different number sequence 2 B .5 it would be half past the hour 15 minutes past the hour would be 1 / 4 or .25

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The freezing point of neon is about -249c . The freezing point of chorine is about 148c higher. What is the approximate freezing

Westkost [7]

Answer:

-101 c.

Step-by-step explanation:

-249 + 148

= -(249 - 148)

= -101 C.

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Answer:

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Step-by-step explanation:

have a great day! :)

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