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yaroslaw [1]
2 years ago
13

Hello can someone help me with this factoring problem? thank you!

Mathematics
1 answer:
Alex2 years ago
8 0
I think this is correct

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If using the method of completing the square to solve the quadratic equation, which number would have to be added to “complete t
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The answer is 80 because you add then subtract
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The point (4,-2) is the vertex of the graph of a quadratic function. The points (8,6) and (2,0) also fall on the graph of the fu
Elina [12.6K]

Answer:

Step-by-step explanation:

y = ax² + bx + c

~~~~~~~

(4, - 2), (8, 6), (2, 0)

a(4²) + b(4) + c = - 2

a(8²) + b(8) + c = 6

a(2²) + b(2) + c = 0

16a + 4b + c = - 2 .............. <em>(1)</em>

64a + 8b + c = 6 ............... <em>(2)</em>

4a + 2b + c = 0 ................. <em>(3)</em>

a = 0.5 ; b = - 4 ; c = 6

<em>y = 0.5x² - 4x + 6</em>

Part A: (0, 6), (6, 0)

Part B: (0,6)

Part C: (6, 0)

Part D: [ 4, ∞ )

4 0
3 years ago
What is the distance between 12 7 and 3 7 !
Vinil7 [7]

Answer:

The answer is 15 units is the answer boom

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Solve the following system:<br> y=1<br> y=-6x-5
Mandarinka [93]

Answer:

x = -1

y = 1

Step-by-step explanation:

<u><em>Since it gives you "y", plug in the number given into the equation:</em></u>

y = -6x - 5

1 = -6x - 5

<u><em>Then, add 5 to both sides:</em></u>

1 = -6x - 5

+5       + 5

________

6 = -6x

<em><u>Divide both sides by -6:</u></em>

6 = -6x

-1 = x

So now you have, x = -1 and y = 1

4 0
3 years ago
Read 2 more answers
How would the factor pairs change if nancy had only 5 posters to arrange?
Romashka [77]

Answer:

Part A) Nancy can arrange the posters in 4 ways

Part B) Nancy can arrange the posters in 2 ways

Step-by-step explanation:

<u><em>The complete question is</em></u>

Nancy has 10 movie posters. She wants to hang them on a wall in equals rows.

A) Find all the ways that she can arrange the posters.

B) How would the factor pairs change if Nancy had only 5 posters to arrange?

Part A) Find all the ways that she can arrange the posters.

we know that

The factors of 10 are

1x10 -----> 1 row of 10 posters

2x5 -----> 2 rows of 5 posters

5x2 -----> 5 rows of 2 posters

10x1 -----> 10 rows of 1 poster

therefore

Nancy can arrange the posters in 4 ways

Part B) How would the factor pairs change if Nancy had only 5 posters to arrange?

we know that

if Nancy had only 5 posters to arrange

then

The factors of 5 are

1x5 -----> 1 row of 5 posters

5x1 -----> 5 rows of 1 poster

therefore

Nancy can arrange the posters in 2 ways

3 0
2 years ago
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