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Zigmanuir [339]
3 years ago
4

Which classification best represents a triangle with side lengths 10 in., 12 in., and 15 in.?

Mathematics
2 answers:
Sindrei [870]3 years ago
6 0

Answer:

It's an acute angled triangle.

Step-by-step explanation:

15^2 = 225

12^2 = 144

10^2 = 100

Adding:

10^2 + 12^2 = 244.

So as 15^2 <  12^2 + 10^2 this is an acute angled triangle.

Harman [31]3 years ago
5 0

Answer:

Acute angled triangle.

Step-by-step explanation:

Sides of a triangle are given by 10 in, 12 in and 15 in.

Now we know that for a triangle if c² > a² + b² then triangle is an Obtuse triangle.

For c² = a² + b²  triangle will be a right angle triangle.

for c² < a² + b² triangle will be an acute triangle.

So by these postulates,

15² = 225

10² = 100

12² = 144

Then 15² < 10² + 12²

Therefore, given triangle is an acute triangle.

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Answer:

6

Step-by-step explanation:

12÷2=6

Hope this helps! :)

8 0
3 years ago
Solve to find x <br> log (3x+5) to base 5= 2log (1-3x) to base 25
Eduardwww [97]

Answer:

x = -2/ 3

Step-by-step explanation:

in order to cancel out the logs they should have common bases

\mathsf{ log_{5}(3x + 5) = 2 log_{25}(1 - 3x)  }

we can write 25 as 5²

\mathsf{ \implies  log_{5}(3x + 5) =  2 \: log_{ {5}^{2} }(1 - 3x)  }

we know that the reciprocal of the exponents of the bases are multiplied to the log

\mathsf{ \implies  log_{5}(3x + 5) =   \frac{1}{\cancel{2} } \times \cancel{2} \: log_{ 5}(1 - 3x)  }

and now since the logs have common bases

\mathsf{ \implies  \cancel { log_{5}}(3x + 5) = \cancel{ log_{ 5}}(1 - 3x)  }

we're left with

\mathsf{ \implies 3x + 5 = 1 - 3x}

\mathsf{ \implies 9x = -4}

<u>x = -2/ 3</u>

8 0
3 years ago
Divide. (-1/5) divided by (-4/5) what is the quotient
worty [1.4K]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the value of a?
Sindrei [870]

Answer:

a=2

Step-by-step explanation:

Firstly, in order to simplify the expression, we should aim to combine the two terms given. In order to do this, both must have the same denominator. We can give them the same denominator by multiplying the second term -\frac{2}{x+2} by \frac{x+2}{x+2}. This way the fraction value remains the same but now has the same denominator as the first term:

-\frac{2}{x+2} *\frac{x+2}{x+2} \\\\=\frac{(-2)(x+2)}{(x+2)(x+2)} \\\\=\frac{-2x-4}{(x+2)^{2}}

From here we can now combine the two terms:

\frac{2x+6}{(x+2)^{2}} +\frac{-2x-4}{(x+2)^{2}} \\\\= \frac{(2x+6)+(-2x-4)}{(x+2)^{2}} \\\\\\=\frac{2x+6-2x-4}{(x+2)^{2}}\\\\= \frac{2}{(x+2)^{2}}

Therefore, a = 2.

Hope this helped!

6 0
2 years ago
Since the opening up of the West, the US population has moved westward. To observe this, we look at the “population center” of t
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Answer:

attached below

Step-by-step explanation:

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