Answer:
Use the drop-down menus to identify the type of context clue that helped you determine the italicized word’s meaning.
Various protuberances, such as rocks, bushes, and ledges, made it easier for the climber to get up the wall.
I made a New Year’s resolution to be generous, but I gave in to avarice instead.
The worst result of the hurricane was the inundation of water that flooded streets and basements.
Step-by-step explanation:
So it will be y1-y2, so 15-20 is -5
Then x1-x2, so 10-15 is -5.
-5/-5 = 1
There’s ya slope : 1
Answer: 24.2° SouthWest
<u>Step-by-step explanation:</u>
First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>
I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.
<u>Perpendicular (x):</u>
cos 35° = adjacent/hypotenuse
cos 35° = x/160
→ x = 160 cos 35°
<u>Angle (θ):</u>
sin θ = opposite/hypotenuse
sin θ = x/320
sin θ = 160 cos 35°/320
θ = arcsin (160 cos 35°/320)
θ = 24.2°
Direction is down (south) and left (west)
I hope this helps you
(-2x^2). (-5x^2)+(-2x^2)(4x^3)
10x^4-8x^5
Answer:
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.
Step-by-step explanation:
Remember that:
- Two lines are parallel if their slopes are equivalent.
- Two lines are perpendicular if their slopes are negative reciprocals of each other.
- And two lines are neither if neither of the two cases above apply.
So, let's find the slope of each equation.
The first basketball is modeled by:
We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:
And divide both sides by four:
So, the slope of the first basketball is -3/4.
The second basketball is modeled by:
Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:
And divide both sides by negative eight:
So, the slope of the second basketball is also -3/4.
Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.