Question

Which of the following is a conjugate for 7 + iSquare root of 2?

Answer 1

Answer:

7 - i$\sqrt{2}$

Step-by-step explanation:

Given a complex number a ± bi then the complex conjugate is

a ∓ bi

Note that the real part remains the same while the sign of the coefficient of the imaginary part is the opposite

Hence conjugate of 7 + i$\sqrt{2}$ is 7 - i$\sqrt{2}$

Answer 2

7- i square root of 2