Answer:
![\frac{5}{29}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B29%7D)
Step-by-step explanation:
Let
represent students playing basketball,
represent students playing baseball.
Then,
, ![n(B)=24](https://tex.z-dn.net/?f=n%28B%29%3D24)
Let
be the total number of students. So,
.
Now,
![P(A)=\frac{n(A)}{n(S)}=\frac{7}{29}](https://tex.z-dn.net/?f=P%28A%29%3D%5Cfrac%7Bn%28A%29%7D%7Bn%28S%29%7D%3D%5Cfrac%7B7%7D%7B29%7D)
![P(B)=\frac{n(B)}{n(S)}=\frac{24}{29}](https://tex.z-dn.net/?f=P%28B%29%3D%5Cfrac%7Bn%28B%29%7D%7Bn%28S%29%7D%3D%5Cfrac%7B24%7D%7B29%7D)
3 students play neither of the sport. So, students playing either of the two sports is given as:
![n(A\cup B)=n(S)-3\\n(A\cup B)=29-3=26](https://tex.z-dn.net/?f=n%28A%5Ccup%20B%29%3Dn%28S%29-3%5C%5Cn%28A%5Ccup%20B%29%3D29-3%3D26)
∴ ![P(A\cup B)=\frac{n(A\cup B)}{n(S)}=\frac{26}{29}](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3D%5Cfrac%7Bn%28A%5Ccup%20B%29%7D%7Bn%28S%29%7D%3D%5Cfrac%7B26%7D%7B29%7D)
From the probability addition theorem,
![P(A\cup B)=P(A)+P(B)-P(A\cap B)](https://tex.z-dn.net/?f=P%28A%5Ccup%20B%29%3DP%28A%29%2BP%28B%29-P%28A%5Ccap%20B%29)
Where,
is the probability that a student chosen randomly from the class plays both basketball and baseball.
Plug in all the values and solve for
. This gives,
![\frac{26}{29}=\frac{7}{29}+\frac{24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{7+24}{29}+P(A\cap B)\\\\\frac{26}{29}=\frac{31}{29}+P(A\cap B)\\\\P(A\cap B=\frac{31}{29}-\frac{26}{29}\\\\P(A\cap B=\frac{31-26}{29}=\frac{5}{29}](https://tex.z-dn.net/?f=%5Cfrac%7B26%7D%7B29%7D%3D%5Cfrac%7B7%7D%7B29%7D%2B%5Cfrac%7B24%7D%7B29%7D%2BP%28A%5Ccap%20B%29%5C%5C%5C%5C%5Cfrac%7B26%7D%7B29%7D%3D%5Cfrac%7B7%2B24%7D%7B29%7D%2BP%28A%5Ccap%20B%29%5C%5C%5C%5C%5Cfrac%7B26%7D%7B29%7D%3D%5Cfrac%7B31%7D%7B29%7D%2BP%28A%5Ccap%20B%29%5C%5C%5C%5CP%28A%5Ccap%20B%3D%5Cfrac%7B31%7D%7B29%7D-%5Cfrac%7B26%7D%7B29%7D%5C%5C%5C%5CP%28A%5Ccap%20B%3D%5Cfrac%7B31-26%7D%7B29%7D%3D%5Cfrac%7B5%7D%7B29%7D)
Therefore, the probability that a student chosen randomly from the class plays both basketball and baseball is ![\frac{5}{29}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B29%7D)
Answer:
(
−
∞
,
∞
)
Step-by-step explanation:
D :)
Because the y values are the same, all we need to take into account is the difference in the length of the x values.
Answer:
Points -2 and -6 on the number line are the two solutions.
Step-by-step explanation:
Use the definition of absolute value as a starting point
![|x|=x\,\,\mbox{for}\,\,x\geq 0\\|x|=-x\,\,\mbox{for}\,\,x](https://tex.z-dn.net/?f=%7Cx%7C%3Dx%5C%2C%5C%2C%5Cmbox%7Bfor%7D%5C%2C%5C%2Cx%5Cgeq%200%5C%5C%7Cx%7C%3D-x%5C%2C%5C%2C%5Cmbox%7Bfor%7D%5C%2C%5C%2Cx%3C0)
To solve the equation, you need to treat the two cases as above:
![|x+4|=x+4=2\,\,\,\mbox{for}\,\,x+4\geq 0\implies x\geq -4\\x+4=2\implies x=-2](https://tex.z-dn.net/?f=%7Cx%2B4%7C%3Dx%2B4%3D2%5C%2C%5C%2C%5C%2C%5Cmbox%7Bfor%7D%5C%2C%5C%2Cx%2B4%5Cgeq%200%5Cimplies%20x%5Cgeq%20-4%5C%5Cx%2B4%3D2%5Cimplies%20x%3D-2)
The solution x=-2 is consistent with the condition x>=-4, so it is the first and valid solution. Now the second case of the absolute value:
![|x+4|=-(x+4)=2\,\,\,\mbox{for}\,\,x+4< 0\implies x](https://tex.z-dn.net/?f=%7Cx%2B4%7C%3D-%28x%2B4%29%3D2%5C%2C%5C%2C%5C%2C%5Cmbox%7Bfor%7D%5C%2C%5C%2Cx%2B4%3C%200%5Cimplies%20x%3C-4%5C%5C-%28x%2B4%29%3D-x-4%3D2%5Cimplies%20x%20%3D%20-6)
Again, the second solution -6 complies with the requirement that x<-4, so it is valid.
Answer:
tan T = 3/4
tan U = 4/3
Step-by-step explanation:
The tangent ratio is opposite / adjacent. The ratio will vary for each angle since the perspective of each angle will be different. For example Angle T has an adjacent side of 4 while Angle U has an adjacent side of 3. The tangent ratios for Angles U and T are listed below:
tan T = 3/4
tan U = 4/3