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timofeeve [1]
3 years ago
11

The student then emptied the flask and dried it once again. To the empty flask she added pieces of a metal until the flask was a

bout three-fourths full. She weighed the stoppered flask and its metal contents and found that the mass was 144.076 g. She then filled the flask with water, stoppered it, and obtained a total mass of 162.292 g for the flask, stopper, metal, and water. Find the density of the metal. a. To find the density of the metal we need to know its mass and volume. We can easily obtain its mass by the method of differences: Mass of metal = ___ g − ____ g = ___g
Chemistry
1 answer:
Anuta_ua [19.1K]3 years ago
7 0
Mass of metal = mass of the flask and stopper with metal - mass of the flask and stopper empty

As per the data given:


Mass of the flask and stopper with metal = 144.076 g


Mass of the flask empty: you did not includ this information, but I searched it and found that the mass of the flask and stopper is 33.695 g


Then, the anwser is:

mass of metal = 144.076 g - 33.695 g = 110.381 g
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A gas is contained in a thick-walled balloon. When the pressure changes from 45.0 bar to 96.0 bar, the volume changes from 1.20
notsponge [240]

P1 * V1 ÷ T1 = P2 * V2 ÷ T2  

45 * 1.20 ÷ 314 = 96 * V2 ÷ 420  

30,144 * V2 = 22,680  

V2 = 22,680 ÷ 30,144  

The new volume is approximately 0.75 liter.

I hope I helped

5 0
3 years ago
Read 2 more answers
Limestone stalactites and stalagmites are formed in caves by the following reaction: Ca2 (aq) 2HCO−3(aq)→CaCO3(s) CO2(g) H2O(l)
Vesna [10]

Answer : The value of \Delta E for this reaction is 36.18 kJ

Explanation :

First law of thermodynamic : It states that the energy can not be created or destroyed, it can only change or transfer from one state to another state.

As per first law of thermodynamic,

\Delta E=q+w

where,

\Delta E = internal energy  of the system

q = heat added or rejected by the system

w = work done

As we are given that:

q = 38.65 kJ

w = -2.47 kJ (system work done on surrounding)

Now put all the given values in the above expression, we get:

\Delta E=38.65kJ+(-2.47kJ)

\Delta E=36.18kJ

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6 0
3 years ago
For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

6 0
3 years ago
Which of the following equations has the correct products and is balanced correctly for a reaction between Na3PO4 and KOH?
ASHA 777 [7]

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Na₃PO₄ is sodium phosphate.  

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According to the mass conservation law, there are same number of atoms on both side of balanced chemical reaction.

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Geothermal energy helps to
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Answer:A

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