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IceJOKER [234]
3 years ago
11

What is the molarity of a 799 mL solution that contains 3.3 moles of NaNO3?

Chemistry
1 answer:
rusak2 [61]3 years ago
8 0

Answer:   I think It might be 1 M???

Explanation:  Sorry I'm not in high school I put the wrong age

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Buck's Turf Care Company mowed 233 lawns over a 11 week period. What is the average weekly rate of mowing lawns?
masya89 [10]

Answer: 21 lawns per week

Explanation:

The average weekly rate refers to how many lawns were mowed per week given that 233 were done in 11 weeks.

Rate will be given by;

= Lawns mowed / Weeks taken

= 233 / 11

= 21 lawns per week

6 0
3 years ago
For most atoms, a stable configuration of electrons is attained when the atom __________. hints hint 1. (click to open) for most
sveticcg [70]

Correct answer: has a completely filled outermost shell

Atoms of the element with complete outermost shells are stable. So, in order to attain stability the atom either loses electrons or gains electrons to completely fill the outermost shell. The stable electronic configuration for the s and p-block elements is exhibited by the noble gases or the group 8 elements. All the unstable atoms try to attain the electronic configuration of the nearest noble gas with completely filled outermost shell.

5 0
3 years ago
Choose the nonmetallic elements from the list. Check all that apply yttrium: oxygen: boron: polonium: argon: gallium: carbon:
BaLLatris [955]

Answer:

B, E, & G

Oxygen, Argon, & Carbon

7 0
3 years ago
Read 2 more answers
Stemscopedia
Alexeev081 [22]
What’s the question
7 0
3 years ago
23) What is the volume of 2.454 x 1024 atoms of nitrogen gas at STP?
earnstyle [38]

Answer:

d) V =  91.3 L

Explanation:

Given data:

Volume of nitrogen = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Number of atoms of nitrogen = 2.454×10²⁴ atoms

Solution:

First of all we will calculate the number of moles of nitrogen by using Avogadro number.

1 mole = 6.022×10²³ atoms

2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms

0.407×10¹ mol

4.07 mol

Volume of nitrogen:

PV = nRT

1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K

V =  91.3 atm.L /1 atm

V =  91.3 L

3 0
3 years ago
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