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Y_Kistochka [10]

3 years ago

10

The following information was reported in an article in a newspaper. A sheriff reported that investigators found 7.5 kilograms o

f cocaine in a car belonging to a man who lives in Virginia. This is a significant amount of cocaine, having a street value of about $1.4 million dollars. Assume that a typical dose contains half a gram of pure cocaine. How much would a dose cost

1 answer:

ruslelena [56]3 years ago

5 0

Answer:

$93.33 per dose

Step-by-step explanation:

$1.4×10⁶/(7.5 kg) × (1 kg)/(1000 g) × (0.5 g)/(1 dose)

= (1.4×10⁶×0.5)/(7.5×10³) $/dose = 700/7.5 $/dose ≈ $93.33/dose

__

Converting dollars per kilogram to dollars per dose involves units conversion from kilograms to doses. We have done it in two steps, first to grams, then to doses.

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Harlamova29_29 [7]

It took 11 hours to change!

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In a game, the player wins if he rolls a 2 on a

natima [27]

Since the die is 6 sided, there’s a 1/6 chance he’ll roll a 2. If we divided 100 by 6, it is a 17% success rate.
24 x 17% is 4.08.

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Double check: 4/24 can be simplified to 1/6, which is the original probability.

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3 years ago

A box contains 3 green marbles, 5 blue marbles, and 7 red marbles. Three marbles are selected at random from the box, one at a t

USPshnik [31]

Answer:

The probability is $P(K) = \frac{ 28 }{195}$

Step-by-step explanation:

From the question we are told that

The number of green marbles is $n_g = 3$

The number of red marbles is $n_b = 5$

The number of red marbles is $n_r = 7$

Generally the total number of marbles is mathematically represented as

$n_t = n_r + n_g + n_ b$

$n_t = 7 + 3 + 5$

$n_t = 5$

Generally total number of marbles that are not red is

$n_k = n_g + n_ b$

=> $n_k = 3 + 5$

=> $n_k = 8$

The probability of the first ball not being red is mathematically represented as

$P(r') = \frac{n_k}{n_t}$

=> $P(r') = \frac{ 8}{15}$

The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

$P(r) = \frac{7}{ 15 -2}$

=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

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3 years ago

Given: sinθ = -3/5, θ is a third quadrant angle, and tan φ = -7/24, φ is a second-quadrant angle; find cos(θ + φ])

Natali [406]

Answer:

First option: cos(θ + φ) = -117/125

Step-by-step explanation:

Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.

Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.

Therefore:

cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)

cos(θ + φ) = (-96/125) - (21/125)

cos(θ + φ) = -96/125 - 21/125

cos(θ + φ) = -117/125

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Svet_ta [14]

The answer would be 50% because you have the choice two options

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