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3 years ago

What affect will adding sugar have on the viscosity of water?

2 answers:

7 0

The addition of some amount of sugar to water increases its viscosity. Viscosity is a term which means the resistance of the liquid to flow. Addition of sugar would give water a certain "stickiness" that would lessen its ability to flow.

Radda [10]3 years ago

4 0

Sugar increases the viscosity of water

hope that helps

You might be interested in

A flask of volume 2.0 liters, provided with a stopcock, contains oxygen at 20 oC, 1.0 ATM (1.013X105 Pa). The system is heated t

leonid [27]

Answer:

1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).

2.6592 grams of oxygen remain in the flask.

Explanation:

Volume of the flask remains constant = V = 2.0 L

Initial pressure of the oxygen gas = $P_1=1.0 atm$

Initial temperature of the oxygen gas = $T_1=20^oC =293.15 K$

Final pressure of the oxygen gas = $P_2=?$

Final temperature of the oxygen gas = $T_2=100^oC =373.15 K$

Using Gay Lussac's law:

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$P_2=\frac{P_1\times T_2}{T_1}=\frac{1 atm\times 373.15 K}{293.15 K}=1.27 atm$

1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).

Moles of oxygen gas = n

$P_1V_1=nRT_1$ (ideal gas equation)

$n=\frac{P_1V_1}{RT_1}=\frac{1 atm\times 2.0 L}{0.0821 atm l/mol K\times 293.15 K}=0.08310 mol$

Mass of 0.08310 moles of oxygen gas:

0.08310 mol × 32 g/mol = 2.6592 g

2.6592 grams of oxygen remain in the flask.

6 0

3 years ago

What mass of iron(II) oxide must be used in the reaction given by the equation below to release 44.7 kJ? 6FeO(s) + O2(g) => 2

zavuch27 [327]

Answer: The mass of iron (II) oxide that must be used in the reaction is 30.37

Explanation:

The given chemical reaction follows:

$6FeO(s)+O_2(g)\rightarrow 2Fe_3O_4(s);\Delta H^o=-635kJ$

By Stoichiometry of the reaction:

When 635 kJ of energy is released, 6 moles of iron (II) oxide is reacted.

So, when 44.7 kJ of energy is released, $\frac{6}{635}\times 44.7=0.423mol$ of iron (II) oxide is reacted.

Now, calculating the mass of iron (II) oxide by using the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of iron (II) oxide = 0.423 moles

Molar mass of iron (II) oxide = 71.8 g/mol

Putting values in above equation, we get:

$0.423mol=\frac{\text{Mass of FeO}}{71.8g/mol}\\\\\text{Mass of FeO}=(0.423mol\times 71.8g/mol)=30.37g$

Hence, the mass of iron (II) oxide that must be used in the reaction is 30.37

7 0

4 years ago

Angela is analyzing the fracture pattern of a window. She notes that the cracks stop when they intersect. Knowing this, what can

diamong [38]

Answer:

b.what type of object broke the glass

Explanation:

The point of intersection of all the fracture patterns of the window speaks to the shape, type and dimension of the object that broke the glass.

7 0

4 years ago

describe a general rule for predicting the motion of an object that is being pushed or pulled by unbalanced forces?

7nadin3 [17]

7th grade activities

Force and Motion

(with Work)

2010-2011

Outline of Topics:

1. Describing Motion: Graphing, Speed and Velocity

2. Describing Motion: Changing Velocity

3. Forces, Their Sizes and Direction

4. Force and Mass

5. Its a grave matter: gravity and inertia

6. Weight and Mass

7. All work and no play: Work and Energy

Appendices

1: 7th Grade Vocabulary Related to Force and Motion

2: Motion Detector Directions

3: Day 1 Graphs with Focus Question at the End

4: Day 1 Data Collection Sheet

5: Day 2 Student Problem Sheet

6: Day 2 Second Set of Problems

7: Day 2 Graphs for is the Velocity Changing

8: Day 3 Student Tables with Questions

9: Day 4 Frame for Science Notebook

10: Day 5 Skateboard Prediction and Actual Sheets

11: Day 6 Data Table

12: Day 7 Student Handout

13: Day 7 Force Arrows

14: Day 8 Data Analysis

15: Uncovering Student Ideas in Physical Science probes

16: National Enquirer advertisements

17: Excerpt from Joy Hakim’s The Story of Science: Newton at the Center, pages 172-183

18: Directions for converting You Tube videos to another media file

First topic: Describing motion

A three-day exercise

Learning goals

Reviewed from 6th grade (day 1):

I can interpret a position versus time line graph to determine types of one-dimensional motion of an object.

I can draw a position versus time line graph given appropriate data.

I can represent changes in motion in a variety of ways, including words, motion arrows, graphs, and by acting out.

(Day 2) I can use the information in a position vs. time graph to determine the speed of an object.

New for 7th grade: I can define velocity.

(Day 3) I can distinguish between speed and velocity.

Topic Word Bank

Speed Motion Velocity Direction Position Graph Distance Vertical Time Horizontal Rate of change Representation Slope Negative Positive

Sequence of Experiences Day 1: Interpretation of a Position/Time Graph Pairs and whole group 10 minutes Day 1: Creation of a Position/Time Graph Lab groups and whole group 25 minutes Day 1: Making Sense of Multiple Representations Whole Group 10 minutes Day 2: Calculating Speed Pairs and whole group 23 minutes Day 2: Differentiating Speed and Velocity Pairs and whole group 18 minutes Day 2: Exit Slip Individually 5 minutes Day 3 Intro Whole class 3 minutes Day 3:Collecting Initial Data In pairs 12 minutes Day 3:Interpreting Data Parts 1 and 2 In pairs, then groups of 4 20 minutes Day 3: Student Challenge Day 3: Class Discussion Whole class 7 minutes Day 4: Intro Day 4:Interpreting Data Parts 3, 4 and 5 Whole class Day 4: Processing Information Individual and Paired Day 4: Class Discussion Whole Class Day 4: Exit Slip Individually 3 minutes

Day 1 Focus Question: What can be learned from different representations of motion?

Materials and Preparation:

For the class:

6 0

3 years ago

what is the correct answer for the calculation of a volume (in ml) with measured numbers 28.58/16x8.0

jeka94

Answer:

Explanation:

the answer is 45 due to the calculation of the master calculation

6 0

3 years ago