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Ivenika [448]
3 years ago
10

What does the law of conservation of energy imply?

Chemistry
2 answers:
liraira [26]3 years ago
8 0
A If I’m not wrong please tell me if I’m right or not
GenaCL600 [577]3 years ago
4 0
Answer a is the correct one
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In a synthesis reaction, one reactant contains 346 J of chemical energy, and one reactant contains 153 J of chemical energy. The
Eduardwww [97]

Answer:

64J of energy must have been released.

Explanation:

Step 1: Data given

One reactant contains 346 J of chemical energy, the other reactant contains 153 J of chemical energy.

The product contains 435 J of chemical energy.

Step 2:

Since the energy is conserved

Sum of energy of Reactants = Energy of Products

Sum of energy of Reactants = 346 J + 153 J = 499 J

The energy of the product = 435 J

435 < 499

This means energy must have been lost as heat.

Step 3: Calculate heat released

499 J - 435 J = 64 J

64J of energy must have been released.

4 0
3 years ago
Which of the following substances found in tobacco smoke stimulates the brain? A. acetone B. toluene C. nicotine D. ammonia Plea
Vaselesa [24]

The answer is C. Nicotine is the substance found in tobacco smoke that stimulates the brain.

7 0
3 years ago
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What is the change in the freezing point of water when 68.5 g of sucrose is
mr Goodwill [35]
The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
7 0
3 years ago
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How many moles of oxygen are needed for the complete combustion of 29.2 grams of acetylene?
podryga [215]

Moles of Oxygen= 2.8075 moles

<h3>Further explanation</h3>

Given

29.2 grams of acetylene

Required

moles of Oxygen

Solution

Reaction(Combustion of Acetylene) :

2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)

Mol of Acetylene :

= mass : MW Acetylene

= 29.2 g : 26 g/mol

= 1.123

From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :

= 5/2 x mol C₂H₂

= 5/2 x 1.123

= 2.8075 moles

7 0
3 years ago
What explains the fact that no machine is 100 percent efficient?
nydimaria [60]
Because some machine might not work and would give you the wrong answer
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3 years ago
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