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alexandr1967 [171]
3 years ago
13

I need help on this someone please help

Chemistry
1 answer:
Murljashka [212]3 years ago
6 0

1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?

Answer:

v = 0.94 mL

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Given data:

Density of soap =  1.06 g/mL.

Mass  = 1 g

Volume = ?

Solution:

d = m/v

v = m/d

v = 1 g/1.06 g/mL

v = 0.94 mL

2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?

Answer:

m = 1370 g

Given data:

Density of soap =  1.37 g/mL.

Mass  = ?

Volume = 1.0 L ( 1000 mL)

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

m = d × v

m = 1.37 g/mL  ×  1000 mL

m = 1370 g

3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?

Answer:

v = 29.2 mL

Given data:

Density of soap =  0.754 g/mL.

Mass  = 22 g

Volume = ?

Formula:

D=m/v

D= density

m=mass

V=volume

Solution:

d = m/v

v = m/d

v = 22 g/0.754 g/mL

v = 29.2 mL

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Explanation:

Transfer of mass A into stagnant film B depends on the availability of driving force.

Whereas driving force is the pressure difference at the surface of A and the bulk.

As,       N_{A} \propto (P_{A1} - P_{A2})

           N_{A} = K_{G} \times (P_{A1} - P_{A2})

Therefore, putting the given values into the above formula as follows.

         N_{A} = K_{G} \times (P_{A1} - P_{A2})

                     = 0.88 \times (0.2 atm - 0.05 atm)

                     = 0.132 mol/h.ft^{2}

Thus, we can conclude that the flux of A from a surface into a mixture of A and B is 0.132 mol/h.ft^{2}

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4 years ago
Gold is alloyed (mixed) with other metals to increase its hardness in making jewelry.
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Answer:

A) 54.04%

B) 13-karat

Explanation:

A) From the problem we have

<em>1)</em> Mg + Ms = 9.40 g

<em>2)</em> Vg + Vs = 0.675 cm³

Where M stands for mass, V stands for volume, and g and s stand for gold and silver respectively.

We can rewrite the first equation using the density values:

<em>3)</em> Vg * 19.3 g/cm³ + Vs * 10.5 g/cm³ = 9.40

So now we have<em> a system of two equations</em> (2 and 3) <em>with two unknowns</em>:

We <u>express Vg in terms of Vs</u>:

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  • Vg = 0.675 - Vs

We <u>replace the value of Vg in equation 3</u>:

  • Vg * 19.3 + Vs * 10.5 = 9.40
  • (0.675-Vs) * 19.3 + Vs * 10.5 = 9.40
  • 13.0275 - 19.3Vs + 10.5Vs = 9.40
  • -8.8 Vs + 13.0275 = 9.40
  • <u>Vs = 0.412 cm³</u>

Now we <u>calculate Vg</u>:

  • Vg + Vs = 0.675 cm³
  • Vg + 0.412 cm³ = 0.675 cm³
  • Vg = 0.263 cm³

We <u>calculate Mg from Vg</u>:

  • 0.263 cm³ * 19.3 g/cm³ = 5.08 g

We calculate the mass percentage of gold:

  • 5.08 / 9.40 * 100% = 54.04%

B)

We multiply 24 by the percentage fraction:

  • 24 * 54.04/100 = 12.97-karat ≅ 13-karat
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3 years ago
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the formula we is as follows:-

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where

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( B ) 0.61 CO2/L

<u>Given data </u>

pressure of CO₂ = 400 Kpa = 3.95 atm

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Solubility = pressure * Kh value of CO₂

                = 3.95 atm * 3.3 * 10⁻² mol / L.atm

                = 0.13 mol/l  CO₂

                = 0.61 CO₂ / L

Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l  CO₂.

Learn more about solubility : brainly.com/question/23946616

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