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Vanyuwa [196]
3 years ago
15

Balancing the following equation. Please use numerical answers

Chemistry
1 answer:
Evgen [1.6K]3 years ago
3 0
This is the answer that is completely drawn out

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Which element is a metalloid?<br> Si<br> Ne<br> Br2<br> Cl2
goldenfox [79]

Answer:

There are 2 answers.  A and C

Explanation:

Si is Silicon, which is a metalloid,

Br2 is Bromine, which is a metalloid

3 0
3 years ago
Consider the following reaction: 2 H2(g) + 2 NO(g) → 2 H2O(g) + N2(g) If the concentration of NO changed from 0.100 M to 0.025 M
Wewaii [24]

Answer: The average rate of the reaction during this time interval is, 0.005 M/s

Explanation:

The given chemical reaction is:

2H_2(g)+2NO(g)\rightarrow 2H_2O(g)+N_2(g)

The expression will be:

\text{Average rate of reaction}=\frac{C_2-C_1}{t_2-t_1}

where,

C_2 = final concentration of NO = 0.025 M

C_1 = initial concentration of NO = 0.100 M

t_2 = final time = 15 minutes

t_1 = initial time = 0 minutes

Putting values in above equation, we get:

\text{Average rate of reaction}=\frac{0.025-0.100}{15-0}

\text{Average rate of reaction}=0.005M/s

Hence, the average rate of the reaction during this time interval is, 0.005 M/s

6 0
3 years ago
For a particular isomer of C8H18, the combustion reaction produces 5113.3 kJ of heat per mole of C8H18(g) consumed, under standa
mart [117]

Answer: The standard enthalpy of formation of this isomer of C_8H_{18}(g) is -210.9 kJ

Explanation:

The given balanced chemical reaction is,

C_8H_{18}(g)+\frac{25}{2}O_2(g)\rightarrow 8CO_2(g)+9H_2O(g)

First we have to calculate the enthalpy of formation of  C_8H_{18}.

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{CO_2}\times \Delta H_f^0_{(CO_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{O_2}\times \Delta H_f^0_{(O_2)+n_{C_8H_{18}}\times \Delta H_f^0_{(C_8H_{18})}]

where,

We are given:

\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.8kJ/mol\\\Delta H^o_f_{(O_2(g)))}=0kJ/mol

Putting values in above equation, we get:

-511.3kJ/mol=[(8\times -393.5)+(9\times -241.8)]-[(\frac{25}{2}\times 0)+(1\times \Delta H_f^0_{(C_8H_{18})}

\Delta H_f^0_{(C_8H_{18})}=-210.9kJ

7 0
4 years ago
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