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VikaD [51]
3 years ago
8

Enter the electron configuration for phosphorus. Express your answer in order of increasing orbital energy as a string without b

lank space between orbitals. For example, the electron configuration of Li could be entered as 1s^22s^1 or [He]2s^1.
Chemistry
1 answer:
statuscvo [17]3 years ago
7 0

Answer:

₁₅P = 1s² 2s² 2p⁶ 3s² 3p³

Explanation:

Phosphorus is the second element of group (v) with atomic number 15 and the electrons per shell are arrange as thus; 2, 8, 5.

The electronic configuration of phosphorus is

₁₅P = 1s² 2s² 2p⁶ 3s² 3p³

Or

₁₅P [Ne] 3s² 3p³

In its first shell I.e 1s shell, it has 2 electrons filling it to s-orbital requirement. In its second shell, electrons fill it in 2s² 2p⁶ filling the second orbital and attaining an octet configuration. The third shell contains 5 electrons filling 3s² 3p³ orbital.

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What is the molecularity of the elementary step X + X + Y → Z?
Anna35 [415]

The molecularity of the elementary step X + X + Y → Z is 3.

<h3>What is Molecularity ?</h3>

Molecularity in chemistry is defined as the total number of molecules that react in an elementary reaction .

In the given question the elementary reaction given is

X + X + Y → Z?

or 2X +Y --> Z

X molecule is 2 and Y molecule is 1 so the molecularity is 2+1 = 3

The molecularity of the elementary step X + X + Y → Z is 3.

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4 0
1 year ago
2.
Arturiano [62]

Answer:

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Explanation:

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6 0
2 years ago
if we react 117 grams of sodium chloride with 340 grams of silver nitrate in a complete reaction what will be the mass, in grams
gavmur [86]

y’all i have this same question someone please help

3 0
2 years ago
The smell of fresh cut pine is due in part to the cyclic alkene called pinene. Given the following data of pinene: Vapor pressur
Sveta_85 [38]

Answer: Heat of vaporization is 41094 Joules

Explanation:

The vapor pressure is determined by Clausius Clapeyron equation:

ln(\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}(\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1= initial pressure at  429 K = 760 torr

P_2 = final pressure at 415 K  = 515 torr

= enthalpy of vaporisation = ?

R = gas constant = 8.314 J/mole.K

T_1= initial temperature =  429 K

T_2 = final temperature = 515 K

Now put all the given values in this formula, we get

\log (\frac{515}{760}=\frac{\Delta H}{2.303\times 8.314J/mole.K}[\frac{1}{429K}-\frac{1}{415K}]

\Delta H=41094J

Thus the heat of vaporization is 41094 Joules

4 0
3 years ago
Hydrogen iodide can decompose into hydrogen and iodine gases. 2 HI(g) H2(g) + 12(g) Kp for the reaction is 0.016. If 0.350 atm o
solniwko [45]

Answer : The total pressure at equilibrium is 0.350 atm

Solution :  Given,

Initial pressure of HI = 0.350 bar

K_p = 0.016

The given equilibrium reaction is,

                             2HI(g)\rightleftharpoons H_2(g)+I_2(g)

Initially                  0.350           0       0

At equilibrium       (0.350-2x)    x       x

The total pressure at equilibrium = (0.350-2x)+x+x=0.350-2x+2x=0.350atm

Thus, the total pressure at equilibrium is 0.350 atm

4 0
2 years ago
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