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VikaD [51]
3 years ago
8

Enter the electron configuration for phosphorus. Express your answer in order of increasing orbital energy as a string without b

lank space between orbitals. For example, the electron configuration of Li could be entered as 1s^22s^1 or [He]2s^1.
Chemistry
1 answer:
statuscvo [17]3 years ago
7 0

Answer:

₁₅P = 1s² 2s² 2p⁶ 3s² 3p³

Explanation:

Phosphorus is the second element of group (v) with atomic number 15 and the electrons per shell are arrange as thus; 2, 8, 5.

The electronic configuration of phosphorus is

₁₅P = 1s² 2s² 2p⁶ 3s² 3p³

Or

₁₅P [Ne] 3s² 3p³

In its first shell I.e 1s shell, it has 2 electrons filling it to s-orbital requirement. In its second shell, electrons fill it in 2s² 2p⁶ filling the second orbital and attaining an octet configuration. The third shell contains 5 electrons filling 3s² 3p³ orbital.

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Lipids that are liquid at room temperature are called oils <br> a. True <br> b. False
erica [24]
The answer to your question is false.
4 0
4 years ago
A 57.9 g sample of glass is cooled by 27.0°C. How much heat does it release?
liberstina [14]

Explanation:

A 57.9 g sample of glass is cooled by 2.70'C how much heat does it release

1560

3 0
3 years ago
How many grams are in .11 moles of Cu
kodGreya [7K]

Answer:

m= 6.9905 = 7 g

Explanation:

The formula is m= M.n

m= mass (g), M= Molar mass (g/mole), n= moles (moles)

Molar mass of Cu is 63.55

=) m= 63.55*0.11

   m= 6.9905 = 7 g

5 0
3 years ago
Answer these please ASAP need help no idea how to do these
STALIN [3.7K]

Answer:

Explanation:

Cu:

Number of moles = Mass / molar masa

2 mol = mass / 64 g/mol

Mass = 128 g

Mg:

Number of moles = Mass / molar masa

0.5 mol = mass / 24 g/mol

Mass =  g

Cl₂:

Number of moles = Mass / molar masa

Number of moles  = 35.5 g / 24 g/mol

Number of moles = 852 mol

H₂:

Number of moles = Mass / molar mass

8 mol  = Mass / 2 g/mol

Mass =  16 g

P₄:

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

O₃:

Number of moles = Mass / molar masa

Number of moles  = 1.6 g /48  g/mol

Number of moles = 0.033 mol

H₂O

Number of moles = Mass / molar masa

Number of moles  = 54 g / 18 g/mol

Number of moles = 3 mol

CO₂

Number of moles = Mass / molar masa

2 mol  =  mass / 124 g/mol

Mass = 248 g

NH₃

Number of moles = Mass / molar masa

Number of moles  = 8.5 g / 17 g/mol

Number of moles = 0.5 mol

CaCO₃

Number of moles = Mass / molar masa

Number of moles  = 100 g / 100 g/mol

Number of moles = 1 mol

a)

Given data:

Mass of iron(III)oxide needed = ?

Mass of iron produced = 100 g

Solution:

Chemical equation:

F₂O₃ + 3CO    →    2Fe  + 3CO₂

Number of moles of iron:

Number of moles = mass/ molar mass

Number of moles = 100 g/ 56 g/mol

Number of moles = 1.78 mol

Now we compare the moles of iron with iron oxide.

                        Fe          :           F₂O₃                

                           2          :             1

                          1.78       :        1/2×1.78 = 0.89 mol

Mass of  F₂O₃:

Mass = number of moles × molar mass

Mass = 0.89 mol × 159.69 g/mol

Mass = 142.124 g

100 g of iron is 1.78 moles of Fe, so 0.89 moles of F₂O₃ are needed, or 142.124 g of iron(III) oxide.

b)

Given data:

Number of moles of Al = 0.05 mol

Mass of iodine = 26 g

Limiting reactant = ?

Solution:

Chemical equation:

2Al + 3I₂   →  2AlI₃

Number of moles of iodine = 26 g/ 254 g/mol

Number of moles of iodine = 0.1 mol

Now we will compare the moles of Al and I₂ with AlI₃.

                          Al            :         AlI₃    

                          2             :           2

                         0.05         :        0.05

                           I₂            :         AlI₃

                           3            :          2

                         0.1           :           2/3×0.1 = 0.067

Number of moles of AlI₃ produced by Al are less so it will limiting reactant.

Mass of AlI₃:                            

Mass = number of moles × molar mass

Mass = 0.05 mol × 408 g/mol

Mass = 20.4 g

26 g of iodine is 0.1 moles. From the equation, this will react with 2 moles of Al. So the limiting reactant is Al.

c)

Given data:

Mass of lead = 6.21 g

Mass of lead oxide = 6.85 g

Equation of reaction = ?

Solution:

Chemical equation:

2Pb + O₂   → 2PbO

Number of moles of lead = mass / molar mass

Number of moles = 6.21 g/ 207 g/mol

Number of moles = 0.03 mol

Number of moles of lead oxide = mass / molar mass

Number of moles = 6.85 g/ 223 g/mol

Number of moles = 0.031 mol

Now we will compare the moles of oxygen with lead and lead oxide.

               Pb         :        O₂

                2          :         1

               0.03     :      1/2×0.03 = 0.015 mol

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.015 mol × 32 g/mol

Mass =  0.48 g

The mass of oxygen that took part in equation was 0.48 g. which is 0.015 moles of oxygen. The number of moles of Pb in 6.21 g of lead is 0.03 moles. So the balance equation is

2Pb + O₂   → 2PbO

   

6 0
3 years ago
A cat that weighs 55 N sits on the top of a cat tree. It is 2 m above a 110N dog. How does the mass of the animals relate to the
Ivahew [28]

*sorry I can't give a full explanation.*

g = 9.8 m/s²

w = m*g

Weight of cat: 55 N = m*9.8

m = 5.61 kg

Weight of dog: 110 N = m*9.8

m = 11.22 kg

There is gravitational potential energy (GPE) acting on the cat since it's at the very top.

GPE of cat = m*g*h = 5.61*9.8*2 = 109.96 J

GPE of dog = m*g*h = 11.22*9.8*0 = 0 J (it's 0 m height because it's on the floor instead of in the tree)

But, if the dog was also 2 m up in the tree, its GPE would be 219.91 J.

As you can see, it's GRAVITATIONAL potential energy is bigger than the cat because it weighs more. Generally, if you were just trying to find the force which is w = m*g (since weight is a force), you would see that the bigger the mass, the bigger the force, and gravity stays the same.

Hope this helped

5 0
3 years ago
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