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kiruha [24]
4 years ago
9

Let a/b and c/d represent two rational numbers. This means a, b, c, and d are (integers or irrational numbers), and b and d are

not 0. This product of the numbers is ac/bd, where bd in not 0. Both ac and bd are (integers or irrational numbers), and bd is not 0. Because ac/bd is the ratio of two (integers or irrational numbers), the product is a rational number.
Choose from one of the two options from the () parentheses!!
Mathematics
1 answer:
antoniya [11.8K]4 years ago
4 0
All of the answer choices are "integers"

a,b,c,d are integers, which is basically the set of positive or negative whole numbers. Though they make the restriction that b and d are not zero

a*c is an integer, so is b*d. This is due to the closure property of multiplication of integers (multiply any two integers you want and it leads to another integer)

ac/bd is the ratio of two integers (ac and bd) where bd is nonzero
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While traveling to Europe, Phelan exchanged 250 US dollars for euros. He spent 150 euros on his trip. After returning
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US dollars=32.66x1.3687

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What 9•8(k+9)-5•7=<br><br> K=?
lara31 [8.8K]
9.8(k+9)−5.7
Distribute:
=(9.8)(k)+(9.8)(9)+−5.7
=9.8k+88.2+−5.7
Combine Like Terms:
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Answer:
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The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

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So the probability written as a simplified fraction is 1/2.

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