Answer:
18.8m
Explanation:
This implies calculating the relative speed first then find the distance d
So
relative speed = 2.75- 1.25 = 1.5 m/s
So assume the distance between them to be say d
so, d/1.5= 12.5
d = 18.8m
The graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.
<h3>
What is average kinetic energy?</h3>
The average kinetic energy of a gas molecule is the energy possesed by the gas due to its relative motion.
Average kinetic energy of gas molecules has a direct relationship with temperature of the gas molecules. As the gas temperature increases, the kinetic energy of the gas increases and consequently, the speed of the gas increases as well.
Thus, the graph will be correct, if it shows a direct relationship between average kinetic energy and temperature of the gas molecules.
Learn more about average kinetic energy here: brainly.com/question/9078768
Answer:
a) The resistance of the calf between the electrodes is 
b) The average resistivity of this part of the leg is 
Explanation:
Hi
a) Using Ohm's law
, solving for
, we obtain 
b) The volume of the calf is like a cylinder, so
, with
and
, therefore
. Then we can use
, this is the average resistivity of this part of the leg.
Answer:
Energy is found as:
E = 1.987·10⁻¹⁹ J
Explanation:
Energy of a single photon of infrared light can be found by using the following formula:

where
E = in Joules
h = Planck's constant = 6.627×10 ⁻³⁴ J
f = frequency in hertz
It can also be written as:

where
c = 2.998×10⁸ ms⁻¹
λ = wavelength
Wavelength is given in the question which is:
λ = 1×10⁻⁶m
Substitute all the values in the Energy formula

Answer:
initial: 1654.6 J, final: 0 J, change: -1654.6 J
Explanation:
The length of the slide is
L = 8.80 ft = 2.68 m
So the height of the child when he is at the top of the slide is (with respect to the ground)

The potential energy of the child at the top is given by:

where
m = 63.0 kg is the mass of the child
g = 9.8 m/s^2 is the acceleration due to gravity
h = 1.13 m
Substituting,

At the bottom instead, the height is zero:
h = 0
So the potential energy is also zero: U = 0 J.
This means that the change in potential energy as the child slides down is
