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sertanlavr [38]
3 years ago
15

When voltage increases and resistance remains constant what must happen to current? A) Current must decrease. B) Current must in

crease. C) Current will remain the same. D) Current is not affected by voltage and resistance.
Physics
2 answers:
nikitadnepr [17]3 years ago
7 0
Current must increase
3241004551 [841]3 years ago
6 0

Explanation :

Current flowing in a circuit is defined as the charge flowing per unit time.

A battery connected to the circuit creates the potential difference.

Resistance basically oppose the flow of current.

We know that the relation between the current, resistance and the voltage is given using the Ohm's law as

V =I R

So, it is clear that the voltage is directly proportional to the current flowing.

So, the correct option is (B) Current must increase.

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4. Which of the following would be a good reference point to describe the motion of a dog?
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ANOTHER RUNNING DOG

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4 0
3 years ago
three condensers are connected in series across a 150 volt supply. The voltages across them are 40,50 and 60 volts respectively,
ioda

Explanation:

Given that,

The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.

(a) Capacitance of capacitor 1,

C_1=\dfrac{Q}{V_1}\\\\C_1=\dfrac{6\times 10^{-8}}{40}\\\\C_1=1.5\times 10^{-9}\ F\\\\C_1=1.5\ nF

Capacitance of capacitor 2,

C_2=\dfrac{Q}{V_2}\\\\C_2=\dfrac{6\times 10^{-8}}{50}\\\\C_2=1.2\times 10^{-9}\ F\\\\C_2=1.2\ nF

Capacitance of capacitor 3,

C_3=\dfrac{Q}{V_3}\\\\C_3=\dfrac{6\times 10^{-8}}{60}\\\\C_3=1\times 10^{-9}\ F\\\\C_3=1\ nF

(b) The equivalent capacitance in series combination is :

\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}+\dfrac{1}{C_3}\\\\\dfrac{1}{C}=\dfrac{1}{1.5}+\dfrac{1}{1.2}+\dfrac{1}{1}\\\\C=0.4\ nF

Hence, this is the required solution.

5 0
3 years ago
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