Answer:
49m/s
59.07 m/s
Step-by-step explanation:
Given that :
Distance (s) = 178 m
Acceleration due to gravity (a) = g(downward) = 9.8m/s²
Velocity (V) after 5 seconds ;
The initial velocity (u) = 0
Using the relation :
v = u + at
Where ; t = Time = 5 seconds ; a = 9.8m/s²
v = 0 + 9.8(5)
v = 0 + 49
V = 49 m/s
Hence, velocity after 5 seconds = 49m/s
b) How fast is the ball traveling when it hits the ground?
V² = u² + 2as
Where s = height = 178m
V² = 0 + 2(9.8)(178)
V² = 0 + 3488.8
V² = 3488.8
V = √3488.8
V = 59.07 m/s
Answer:
9-6.92820323i Nothing else can be done.
Step-by-step explanation:
-48 is not a perfect square but 81 is a square. When you try to square -48 it comes to be 6.92820323i.
Answer:
(2,1)
Step by step explanation:
Please find the attachment.
We have been given that line 
is horizontal and passes through point (1,1). Line 
is vertical and passes through point (2,2). We are asked to find point of intersection of line and line .
Line is a horizontal line so y-coordinate will be 1 for any value of x. Line is a vertical line, so x-coordinate will be 2 for any value of y.
Therefore, intersection point of both lines will include x-coordinate of line and y-coordinate of line that is (2,1).
Answer:
x² + y² + 2x + 8y − 47 = 0 B. x²+y² − 2x − 8y
Step-by-step explanation:
