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Hitman42 [59]
4 years ago
11

Which system works similar to a refrigeration system

Physics
2 answers:
mote1985 [20]4 years ago
5 0
It might be a freezer system.
Vilka [71]4 years ago
4 0
I wanna say a thermostat..Hope it help!!!
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If 500 J of energy is added to a 20 kg sample of copper, what is the increase in temperature? The specific heat of copper is 387
Sedaia [141]

Answer:

I have put the answer and solution in the files part!

7 0
3 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.390 mm wide. The diffraction pattern is observed
pashok25 [27]

Answer:

Y = 5.03 x 10⁻³ m = 5.03 mm

Explanation:

Using Young's Double-slit formula:

Y = \frac{\lambda L}{d}

where,

Y = Fringe Spacing = Width of bright fringe = ?

λ =  wavelength = 633 nm = 6.33 x 10⁻⁷ m

L = Screen distance = 3.1 m

d = slit width = 0.39 mm = 3.9 x 10⁻⁴ m

Therefore,

Y = \frac{(6.33\ x\ 10^{-7}\ m)(3.1\ m)}{3.9\ x\ 10^{-4}\ m}

<u>Y = 5.03 x 10⁻³ m = 5.03 mm</u>

8 0
3 years ago
Assume that the ammeter in the figure below is removed and the current that flows through the 4.0Ω path, I3, is unknown. Determi
qaws [65]

The circuit is in parallel connection

Equivalent resistance = 1/Req = 1/R1 + 1/R2 + 1/R3

From the information given,

R1 = 5

R2 = 2

R3 = 4

1/Req = 1/5 + 1/2 + 1/4 = (4 + 10 + 5)/20 = 19/20

Req = 20/19 = 1.053 ohms

I = V/R

Given that V = 12,

Current flow through circuit = 12/1.053 = 11.4 A

I1 + I2 + I3 = 11.4

I1 = 12/5 = 2.4 A

I2 = 12/2 = 6 A

I3 = 12/4 = 3A

8 0
1 year ago
Ley de Coulomb para describir y predecir fuerzas gravitacionales y electromacneticas​
chubhunter [2.5K]

Answer:

Explanation:

i dont speak spanish :P

4 0
3 years ago
A 4-kg block and a 2-kg block can move on the horizontal frictionless surface. The blocks are accelerated by a+12-N force that p
lozanna [386]

Answer:

F_n = -4 N

Explanation:

Net external force that exerted on the block is given as

F_{net} = (m_1 + m_2) a

here we know that

F = 12 N

m_1 = 4 kg

m_2 = 2 kg

now we have

12 = (4 + 2) a

so we have

a = 2 m/s^2

now the force exerted by bigger block on smaller block is given as

F_n = ma

F_n = (2 \times 2)

F_n = 4 N

now we know that two blocks will exert equal and opposite force on each other

so here the force exerted by 2 kg block on 4 kg block will be

F_n = -4 N

5 0
3 years ago
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