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Art [367]
3 years ago
8

A ball is rolling horizontally at 3.00 meters per second as it leaves the edge of a tabletop 0.750 meter above the floor. The ba

ll lands on the floor 0.391 second after leaving the tabletop. What is the magnitude of the ball’s acceleration 0.200 second after it leaves the tabletop? [Neglect friction.]
Physics
2 answers:
NikAS [45]3 years ago
8 0

Answer: 9.81m/s^2

Explanation: since it’s free fall and friction is neglected, the magnitude of the ball’s acceleration will be equal to the general acceleration due to gravity which is 9.81m/s^2

Reil [10]3 years ago
5 0

Answer:

9.8 m/s^{2}

Explanation:

Any object in free-fall will accelerate due to gravity. Acceleration due to gravity is equal to 9.8 m/s^{2}.

This numerical value for the acceleration of a free-falling object is given a special name "the acceleration of gravity" - the acceleration for any object moving under the sole influence of gravity. The value for the acceleration of gravity is most accurately known as 9.8 m/s^{2}. There are slight variations in this numerical value (to the second decimal place) that are dependent on altitude.

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A 4. 0 nc positive point charge is located at point a in the figure. (figure 1) what is the electric potential at point b?.
algol [13]

The electric potential at point b experienced by the charge cab be determined using the formulas given.

<h3>Electric potential</h3>

The electric potential of a point charge is the work done in moving the charge from infinity to certain point against the electric field.

V = Ed

V = (F/q)d

V = (Fd)/q

where;

  • V is the electric potential
  • F is electric force
  • E is the electric field
  • q is the charge

Thus, the electric potential at point b experienced by the charge cab be determined using the formulas given.

Learn more about electric potential here: brainly.com/question/14306881

7 0
2 years ago
The speed of a transverse wave on a string is 450 m/s, and the wavelength is 0.19 m. The amplitude of the wave is 1.6 mm. How mu
tigry1 [53]

Answer: 2.22s

Explanation: wave speed = 450 m/s, A = amplitude = 1.6mm, λ= wavelength = 0.19m

Wave speed = distance traveled / time taken

Distance traveled = 1km = 1000 m

450 = 1000/ t

t = 1000/ 450 = 2.22s

5 0
3 years ago
A point on a wheel of radius 40 cm that is rotating at a constant 5.0 revolutions per second is located 0.20 m from the axis of
Margarita [4]

Answer:

197.2 m/s^2

Explanation:

The centripetal acceleration of a point moving by circular motion is given by:

a=\omega^2 r

where

\omega is the angular velocity

r is the distance from the axis of rotation

The point on the wheel makes 5.0 revolutions per second, so the frequency is

f=\frac{5}{1}=5 Hz

and the angular velocity is

\omega=2\pi f = 2\pi (5)=31.4 rad/s

While the distance of the point from the axis of rotation is

r=0.20 m

Substituting, we find the acceleration:

a=(31.4)^2(0.20)=197.2 m/s^2

5 0
3 years ago
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If a stone dropped into a well reaches the water's surface after 3.0 seconds, how far did the stone drop before hitting the wate
Ulleksa [173]
<span>s= 0.5 at^2
</span>
0.5 x 9.81 x 3^2 = 44m
8 0
3 years ago
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A weightlifter raises a 200-kg barbell with an acceleration of 3 m/s^2. How much force does the weightlifter use to raise the ba
lesya692 [45]

F = mass x acceleration

We have mass = 200kg

and acceleration = 3 m/s^2 so...

F = (200)(3)

F = 600 N

4 0
3 years ago
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