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KatRina [158]
3 years ago
15

Which change to an object would double its potential energy?

Physics
2 answers:
zysi [14]3 years ago
4 0

Answer:

D

Explanation:

Increasing its height to twice its original value

Ket [755]3 years ago
4 0

Answer:the right answer is D

Explanation:

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The electric potential energy stored in the capacitor of a defibrillator is 73 j, and the capacitance is 120 f. what is the pote
pychu [463]

The relationship between electrical potential energy (PE), capacitance (C), and potential difference (V) can be expressed through the equation,

<span>                                  V  = PE / C</span>

V is equal to the quotient of potential energy and capacitance.

 

When we substitute the known values from the item,

<span>                               V =  73 J/ 120 C</span>

<span>                                    V = 0.61 J/C</span>

<span>Thus, the voltage or potential difference is equal to 0.61 V. </span>

6 0
4 years ago
A person walks 20.0° north of east for 3.20 km. How far would she have to walk due north and due east to arrive at the same loca
aivan3 [116]

Answer:

1.09 km, 3 km

Explanation:

displacement, d = 3.20 km at 20° North of east

A vector quantity has two components one along the x axis and the other is along Y axis. the component along X axis is called the horizontal component and it is due east.

The component along y axis is called vertical component and it is due North.

Displacement due North, dy = 3.20 Sin 20° = 1.09 km

Displacement due east, dx = 3.20 Cos 20° = 3 km

8 0
4 years ago
Help needed pls and thxs
algol13
Erosion:
A.) Is the same as weathering
3 0
4 years ago
If a ball is thrown straight up into the air with an initial velocity of 40 ft/s, it height in feet after t second is given by y
Tasya [4]
We should first calculate the highest point that ball reaches. 
y' = 40 - 32t = 0
t = 40/32 = 1,25s
y = 25 feet.

To calculate average velocity we use simple formula:
Vav=s/t   where s is traveled distance by the time t.



for t=2  we calculate y
y = 16
(i)  for t = 2,5     y = 0
Vav = 16/0.5 = 32 feet/s
(ii) for t = 2.1     y = 13.44
Vav = 2.56/0.1 = 25.6 feet/s
(iii) for t = 2.01  y = 15.7584
Vav = 0.2416/0.01= 24.16 feet/s

it seems like the answer would be 24 feet/s. There is a way to calculate that.
5 0
3 years ago
A projectile is fired at an angle such that the vertical component of its velocity
mestny [16]

Answer:

<em>It takes 3 seconds to reach its high point</em>

Explanation:

<u>Projectile Motion</u>

In a projectile motion (or 2D motion), the object is launched with an initial angle θ and an initial velocity vo.

The components of the velocity are

v_{ox}=v_o\cos\theta

v_{oy}=v_o\sin\theta

The speed in the horizontal direction at any time t is:

v_y=v_o\sin\theta-g.t

The time taken to reach the maximum height is when vy=0, or:

\displaystyle t_m=\frac{v_o\sin\theta}{g}

We are given the y-component of the velocity, thus:

\displaystyle t_m=\frac{30~m/s}{10~m/s^2}

t_m=3~s

It takes 3 seconds to reach its high point

3 0
3 years ago
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