The noble gas notation of an element includes a noble gas as a condensed way to describe the electronic configuration of an element. IN this case, the nearest noble gas is xenon with an atomic number of 54. Hg's atomic number is 80 so we need 26 more. In this case, after [Xe], the configuration starts with 6s². Hence to complete the configuration the answer is [Xe] 6s2 4f14 5d10
Answer:
combining wax
Explanation:
Candles burn through an efficient combustion process by combining wax, a poor conductor of heat that melts just above room temperature, with a wick, an absorbent material that will absorb liquid wax and transfer it toward the candles flame while its burning. when a candles wick is lit, the heat from above it. and I'm not a good explainer sorry if I got it wrong
Answer:
The answer is
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Explanation:
The Ka of an acid when given the pH and concentration can be found by
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where
c is the concentration of the acid
From the question
pH = 5.82
c = 0.010 M
Substitute the values into the above formula and solve for Ka
We have
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Multiply through by - 2
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Find antilog of both sides
We have the final answer as
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Hope this helps you
Answer:
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Answer:
We need 7.5 mL of the 1M stock of NaCl
Explanation:
Data given:
Stock = 1M this means 1 mol/ L
A 0.15 M solution of 50 mL has 0.0075 moles NaCl per 50 mL
Step 2: Calculate the volume of stock we need
The moles of solute will be constant
and n = M*V
M1*V1 = M2*V2
⇒ with M1 = the initial molair concentration = 1M
⇒ with V1 = the volume we need of the stock
⇒ with V2 = the volume we want to make of the new solution = 50 mL = 0.05 L
⇒ with M2 = the concentration of the new solution = 0.15 M
1*V1 = 0.15*(50)
V1 = 7.5 mL
Since 0.0075 L of 1M solution contains 0.0075 moles
50 mL solution will contain also 0.0075 moles but will have a molair concentration of 0.0075 moles / 0.05 L =0.15 M
We need 7.5 mL of the 1M stock of NaCl
