Answer:
K+
Explanation:
Potassium(an alkali metal) belongs to element in group 1 and period 4 in the periodic table. It has to release one electron to attain noble configuration.
Answer:
It is the sum of internal energies of two or more substances
Explanation:
Answer:
<u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>
Explanation:
Step 1: What are hydrogen ion donor and acceptor
in the following reaction we see that:
⇒ H2PO4- is more likely to give a H+ ion to form HPO42-.
⇒HPO42- is more likely to take a H+ ion, to form H2PO4-
The reaction of an acid in water solvent is described as a dissociation
:
HA ⇔ H+ + A-
⇒where HA is a proton acid
So, H2PO4- = HA and HPO42- = A-
Acids are proton donors. So, <u>H2PO4- is a proton donor and HPO42_ is a proton acceptor</u>
Answer:
2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.
12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution
Explanation:
First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:
- Ca: 40 g/mole
- F: 19 g/mole
So the molar mass of CaF₂ is:
CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole
Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

moles=2.05*10⁻⁵
<u><em>2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.</em></u>
Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

mass of CaF₂= 1000 g
Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

moles=12.82
<u><em>12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution</em></u>
Balanced chemical reaction: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g).
1) In a chemical reaction, chemical equilibrium is the state in which both reactants (methane CH₄) and products (ethyne C₂H₂ and hydrogen H₂) are present in concentrations which have no further tendency to change with time.
2) At equilibrium, both the forward and reverse reactions are still occurring.
3) Reaction rates of the forward and backward reactions are equal and there are no changes in the concentrations of the reactants and products.