Write skeleton equations for the following reactions

A 15.0 g sample of nickel metal is heated to 100.0 degrees C and dropped into 55.0 g of water, initially at 23.0 degrees C. Assu

OLEGan [10]

Answer: The final temperature of nickel and water is $25.2^{o}C$ .

Explanation:

The given data is as follows.

Mass of water, m = 55.0 g,

Initial temp, $(t_{i}) = 23^{o}C$ ,

Final temp, $(t_{f})$ = ?,

Specific heat of water = 4.184 $J/g^{o}C$ ,

Now, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$

Also,

mass of Ni, m = 15.0 g,

Initial temperature, $t_{i} = 100^{o}C$ ,

Final temperature, $t_{f}$ = ?

Specific heat of nickel = 0.444 $J/g^{o}C$

Hence, we will calculate the heat energy as follows.

q = $mS \Delta t$

= $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$

Therefore, heat energy lost by the alloy is equal to the heat energy gained by the water.

$q_{water}(gain) = -q_{alloy}(lost)$

$55.0 g \times 4.184 J/g^{o}C \times (t_{f} - 23^{o}C)$ = -( $15.0 g \times 0.444 J/g^{o}C \times (t_{f} - 100^{o}C)$ )

$t_{f} = \frac{25.9^{o}C}{1.029}$

= $25.2^{o}C$

Thus, we can conclude that the final temperature of nickel and water is $25.2^{o}C$ .

6 0

3 years ago

The distance from dalton, ga to Dallas, tx is 1308 km. What is the distance in miles

Oksana_A [137]

Answer:
812.754 miles

Why:
0.621371 miles per km

4 0

3 years ago

How much energy (in JJ) is lost when a sample of iron with a mass of 29.2 gg cools from 79.0 ∘C∘C to 27.0 ∘C∘C?

Anna35 [415]

Answer:

- 0.674 kJ.

Explanation:

The equation used to solve this problem is:

Q = mCΔT

where,

Q = amount of heat

m = mass of the substance

C = specific heat capacity

ΔT = change in temperature

= Temp.f - Temp.i

Given:

m = 29.2 g

Temp.i = 79°C

Temp.f = 27°C

Cp(iron) = 0.444 J/g.K

Q = mCΔT

ΔT = 27.0°C - 79.0°C

= -52°C

= 29.2 * 0.444 * -52

Q = - 674.17 J

= 0.674 kJ.

6 0

3 years ago

Which of the following is not a conjugate acid-base pair? A) NH4+/NH3 B) H30-OH OC) H2SO3/HSO3 D) C2H302-/HC2H302

raketka [301]

Answer : The option (d) is not a conjugate acid-base pair.

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

$NH_4^++OH^-\rightleftharpoons NH_3+H_2O$

In this reaction, $NH_4^+/NH_3$ are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

$H_3O^++OH^-\rightleftharpoons H_2O+H_2O$

In this reaction, $H_3O^+/OH^-$ are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

$H_2SO_3+OH^-\rightleftharpoons HSO_3^-+H_2O$

In this reaction, $H_2SO_3/HSO_3^-$ are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

$C_2H_3O_2^-+H_2O\rightleftharpoons HC_2H_3O_2+OH^-$

In this reaction, $C_2H_3O_2^-/HC_2H_3O_2$ are act as a conjugate base-acid.

Hence, from this we conclude that, the option (d) is not a conjugate acid-base pair but it is a act as conjugate base-acid.

6 0

3 years ago

2. In the lungs, when blood enters a capillary from a vein it<br> has

antoniya [11.8K]

Answer:

This is called the pulmonary circulation. From your pulmonic valve, blood travels to the pulmonary artery to tiny capillary vessels in the lungs. Here, oxygen travels from the tiny air sacs in the lungs, through the walls of the capillaries, into the blood.

Explanation:

4 0

4 years ago