Answer with Step-by-step explanation:
a.

Taking both sides log

Using identity:

Using identity:


b.
We know that

Using identity

c.

Substitute the values then we get

By using 
Hence, 
Answer:
Step-by-step explanation:
An x value of 0 can only be plugged into the equation that has a domain that includes 0. The first function's domain is between -2 and -4, so 0 is not included in that domain. In the third function, the domain is between 1 and 3, so 0 is not included in that domain, either. The middle function's domain does include 0 (0 falls between -2 and 1) so we can only evaluate this function at an x value of 0.
g(0) = -0 - 1 so
g(0) = -1
Answer:
X=11º
Y=26º
Step-by-step explanation:
77=7x 11=x
180=77+77+y 26=y
Answer:
The height of the prism is 
Step-by-step explanation:
we know that
The volume of the rectangular prism is equal to

In this problem we have



substitute in the formula and solve for H

![H=5,376/[(14)(16)]](https://tex.z-dn.net/?f=H%3D5%2C376%2F%5B%2814%29%2816%29%5D)

Answer:
The width of the window should be
and the height of the window should be 
Step-by-step explanation:
we know that
The circumference of a semicircle (window) is equal to

we have that


substitute and solve for r


so
the width of the window is equal to the diameter of the semicircle
so
The width of the window should be
and the height of the window should be 