It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.
<u>Explanation:</u>
2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂
We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.
![100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}](https://tex.z-dn.net/?f=100%20g%20%5Ctext%20%7B%20of%20%7D%20A%20g%20N%20O_%7B3%7D%20%5Ctimes%20%5Cfrac%7B2%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20N%20O_%7B3%7D%7D%7B169.87%20g%20A%20g%20N%20O_%7B3%7D%7D%20%5Ctimes%20%5Cfrac%7B2%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20C%20l%7D%7B1%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20N%20O_%7B3%7D%7D%20%5Ctimes%20%5Cfrac%7B143.32%20g%20A%20g%20C%20l%7D%7B1%20%5Ctext%20%7B%20mol%20%7D%20A%20g%20C%20l%7D)
= 337.5 g AgCl
In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.
It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.
- E(Bonds broken) = 1371 kJ/mol reaction
- E(Bonds formed) = 1852 kJ/mol reaction
- ΔH = -481 kJ/mol.
- The reaction is exothermic.
<h3>Explanation</h3>
2 H-H + O=O → 2 H-O-H
There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb
- E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
- ΔH(Breaking bonds) = +1371 kJ/mol
Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release
- E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.
- ΔH(Forming bonds) = - 1852 kJ/mol
Heat of the reaction:
is negative. As a result, the reaction is exothermic.
They are organized into crystals hope i helped
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