Answer: 23 g
the mol of Fe is 11,5/56 = 23/112 (mol)
the mol of CO is 
(mol)
we have:
Fe2O3 + 3CO => 2Fe + 3CO2
23/112 69/112 23/56
=> the mol of Fe is 23/56 mol
=> the mass of Fe is 23/56.56 = 23 (g)
Explanation:
<u>Charge:</u>
An electron has a negative charge and a <em>n</em>eutron has a <em>n</em>eutral charge.
<u>Size:</u>
Electrons have a really small mass whereas the neutron has a mass of about 1 amu.
<u>Location:</u>
Neutrons are found in center of an atom, but electrons are around it.
<u>Number:</u>
The number of electrons and neutrons in atom varies.
Let the ratio of grams of hydrogen per gram of carbon in methane be M, we know that:
M = 0.3357 g / 1 g
Next, lets represent the grams of hydrogen per gram of carbon in ethane be E. The final piece of information we have is:
M / E = 4/3
If we cross multiply,
3M = 4E
Now, substituting the value of M from earlier and solving for E,
E = (3 * 0.3357) / 4
E = 0.2518
There are 0.2518 grams of hydrogen per gram of carbon in ethane.
A proton is the same as an H+ ion, and Arrhenius acids are the ones that release H+ in solution, so the answer is A
Answer:
(a) rate = 4.82 x 10⁻³s⁻¹ [N2O5]
(b) rate = 1.16 x 10⁻⁴ M/s
(c) rate = 2.32 x 10⁻⁴ M/s
(d) rate = 5.80 x 10⁻⁵ M/s
Explanation:
We are told the rate law is first order in N₂O₅, and its rate constant is 4.82 x 10⁻³s⁻¹ . This means the rate is proportional to the molar concentration of N₂O₅, so
(a) rate = k [N2O5] = 4.82 x 10⁻³s⁻¹ x [N2O5]
(b) rate = 4.82×10⁻³s⁻¹ x 0.0240 M = 1.16 x 10⁻⁴ M/s
(c) Since the reaction is first order if the concentration of N₂O₅ is double the rate will double too: 2 x 1.16 x 10⁻⁴ M/s = 2.32 x 10⁻⁴ M/s
(d) Again since the reaction is halved to 0.0120 M, the rate will be halved to
1.16 x 10⁻⁴ M/s / 2 = 5.80 x 10⁻⁵ M/s
