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Dafna11 [192]
3 years ago
15

Show that, with appropriate coefficients, the two reactions can be summed to give the overall oxidation of SO2 by O2 to give SO3

. Give the equation for the final overall oxidation of SO2 by O2 to give SO3 as your answer. Express your answer as a chemical equation. Identify all of the phases in your answer.
Chemistry
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

See explanation

Explanation:

We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;

Step 1

2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)

Step 2

2NO(g) + O2(g) -------> 2NO2(g)

So, the overall reaction equation is;

2SO2(g) + O2(g) ------> 2SO3(g)

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A high pressure gaseous synthesis of hydrazine (H₄N₂) is governed by the following equilibrium: <img src="https://tex.z-dn.net/?
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Answer:

The quantity of hydrazine formed is 3.16 mmoles

Explanation:

This is a typical equilibrium problem.

Initially we have 10 moles of ammonia, so I don't have any hydrazine or hydrogen. During the reaction, an X amount of moles of ammonia reacts to give half moles of hydrazine and hydrogen. The ratio of reagent to product is 2 to 1.

In equilibrium I will have the 10 moles of ammonia - X and X/2 moles of hydrazine and hydrogen.

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Initial    10m            -              -

React     x              x/2         x/2

Eq       10-x             x/2        x/2

Since the volume is 1L the concentration is molar. REMEMBER THAT  IN EQUILIBRIUM WE WORK WITH MOLAR CONCENTRATIONS

The expression of Kc is [H₄N₂]. [H2] / [NH3]²

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1x10⁻⁷ = 1/4x² / 100-20x+x²

1x10⁻⁷ (100-20x+x²) = 1/4x²

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1/4 = a ; 2x10⁻⁶ = b ; -1x10⁻⁵ = c

(-b +- √(b²-4ac))/2a

x1 = 6.32x10⁻³

x2 = -6.32x10⁻³

Concentrations can not be negative, so we take x1

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[H₄N₂] = 6.32x10⁻³/2 = 3.16x10⁻³ moles

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3.16x10⁻³ moles . 1000 = 3.16 mmoles

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