<h3>
Answer:</h3>
3.03 × 10²⁵ formula units KCl
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Unit 0</u>
- Reading a Periodic Table
- Writing Compounds
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
50.3 mol KCl (Potassium chloride)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
<u />
= 3.02907 × 10²⁵ formula units KCl
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
3.02907 × 10²⁵ formula units KCl ≈ 3.03 × 10²⁵ formula units KCl
Order, sensitivity or response to the environment, reproduction, growth and development, regulation, homeostasis, and energy processing.
The mass of water that contains 2.5×10²⁴ atoms of Hydrogen is 74.79 g
<h3>Avogadro's hypothesis </h3>
From Avogadro's hypothesis,
6.02×10²³ atoms = 2 g of H
Therefore,
2.5×10²⁴ atoms = (2.5×10²⁴ × 2) / 6.02×10²³
2.5×10²⁴ atoms = 8.31 g of H
<h3>How to determine the mass of water </h3>
- 1 mole of water H₂O = (2×1) + 16 = 18 g
- Mass of H in 1 mole of water = 2 g
2 g of H is present in 18 g of water.
Therefore,
8.31 g of H will be present in = (8.31 × 18) / 2 = 74.79 g of water.
Thus, 2.5×10²⁴ atoms of Hydrogen is present in 74.79 g of water.
Learn more about Avogadro's number:
brainly.com/question/26141731
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