3 years ago

Factor this trinomial completely.

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

Answer:

2(x^2+3x+2) = 2(x+1)(x+2)

Answer is D.

Step-by-step explanation:

You might be interested in

H = (4 x + 3 y) + to make x the subject

Likurg_2 [28]

X=h/4 -3y/4 hope that helped

3 0

3 years ago

Write an equation of a circle with a center at (2, - 4) and a radius of 4.

fgiga [73]

9514 1404 393

Answer:

(x -2)^2 +(y +4)^2 = 16

Step-by-step explanation:

The equation of a circle with center (h, k) and radius r is ...

(x -h)^2 +(y -k)^2 = r^2

You have (h, k) = (2, -4) and r = 4, so your equation is ...

(x -2)^2 +(y -(-4))^2 = 4^2

(x -2)^2 +(y +4)^2 = 16

6 0

3 years ago

Pls answer cggjtzajyrzmkyrkr

tia_tia [17]

Answer: D

Step-by-step explanation:

You save the most money with option D. Not in the long run though

4 0

3 years ago

Read 2 more answers

If the measure of angle JKP is 3r + 12 and the measure of angle PKN is 4r - 2, what is the measure of angle JKN

il63 [147K]

Answer should be 108 would you mind sending a visual so I can be sure

8 0

3 years ago

Hi! I was wondering if you could help with this question please :)

Makovka662 [10]

Answer:

$R=\frac{QJ}{I^2t}$

Step-by-step explanation:

So we have the equation:

$Q=\frac{I^2Rt}{J}$

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

$(J)Q=(J)\frac{I^2Rt}{J}$

Simplify the right:

$JQ=I^2Rt$

We can rewrite our equation as:

$JQ=R(I^2t)$

So, to isolate the R variable, divide both sides by I²t:

$\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}$

The right side cancels, so:

$R=\frac{QJ}{I^2t}$

And we are done!

7 0

3 years ago