Answer:
The desired point is thus (-1/2, -5).
Step-by-step explanation:
The x-component of this directed line segment is 2 - (-8), or 10, and the y-component is -7 - (1), or -8. This segment is in Quadrant II, since the x-component is positive and the y-component is negative.
The point of interest is (3/4) of the way in the positive x-direction from x = -8. We can express this symbolically as -8 + (3/4)(10), or -8 + 7.5, or -1/2.
The point of interest is 3/4 of the way in the negative y direction from 1, or:
1 + (3/4)(-8), or 1 - 6, or -5.
The desired point is thus (-1/2, -5).
Answer:36
Step-by-step explanation:36÷ -4 = -9
(2x + 3y = 12) x (-2)
(4x - 3y = 6) x 1
-4x - 6y = -24
4x - 3y = 6
You can cancel out the x values by adding the two equations together.
(-4x + 4x) + (-6y - 3y) = (-24 + 6)
-9y = -18
y = 2
Solve for x now...
4x - 3(2) = 6
4x - 6 = 6
4x = 12
x = 3
Check... (x = 3, y = 2)
2(3) + 3(2) = 12
6 + 6 = 12
12 = 12 <- this works!
4(3) - 3(2) = 6
12 - 6 = 6
6 = 6 <- this works!
|-5| is equivalent to 5, since that is how far -5 is from 0.
So, the question is simplified to: How far away is -5 from 5?
We get 5-(-5)=10.
Remember, absolute value is always positive (expect for 0) and the distance between two numbers is always positive (expect for 0).
