<span>4n − 3
4 × 5 -3 = 17
</span>
The distance between the points (2,1) and (14,6) on a coordinate is C. 13 units
11 + 8 × {45 + 4 × [3 + 8 × (12 × 13 - 8 × 14) - 37]} + 1234 =
= <span>11 + 8 × {45 + 4 × [3 + 8 × (156 - 112) - 37]} + 1234 =
</span>= <span>11 + 8 × {45 + 4 × [3 + 8 × 44 - 37]} + 1234 =
</span>
= <span>11 + 8 × {45 + 4 × [3 + 352 - 37]} + 1234 =
</span>
= <span>11 + 8 × {45 + 4 × [355 - 37]} + 1234 =
</span>
= <span>11 + 8 × {45 + 4 × 318} + 1234 =
</span>
= <span>11 + 8 × {45 + 1272} + 1234 =
</span>
= <span>11 + 8 × 1317 + 1234 =
</span>= <span>11 + 10536 + 1234 = 10547 + 1234 = 11781
</span>
Mid point formula
(x1 + x2) , (y1+y2)
--------- --------
2 2
Thus for x it would be (6+(-2)) /2 or 4/2 or 2.
For y (-4 + 4) / 2 or 0 / 2 or 0.
Mid point is (2,0)
Is this 2x to the power of 2?
if it is then this is easy
list it out (just to show you how its solved)
2x^2*4x^2
2x^2*(-12x)
2x^2*10
then list the other one
-5x*<span>4x2
</span>-5x*(-12x)
-5x*10
so the whole answer is
8x^4+(-24x^3)+(-20x^3)+20x^2+60x^2+(-50x)
