All categories

3 years ago

Graph y = | x | + 5

Mathematics

2 answers:

Elanso [62]3 years ago

6 0

Answer:

(0,5) (0,-5)

Step-by-step explanation:

tekilochka [14]3 years ago

6 0

Answer:

Step-by-step explanation:

The basic (parent) function here is y = |X|, the absolute value function.

This function has a v-shape that opens up and has its vertex at (0, 0).

Each leg is at a 45° angle to the x - axis. Draw this.

Then translate the entire graph upward by 5 units. The result will be the graph of y = | x | + 5.

You might be interested in

Solve the absolute value equation. Check for extraneous solutions: |9x-3|=12

STatiana [176]

ANSWER: x=5/3, -1. Good luck. Hope this suffices.

Explanation for x=-1: |9x-3|=12. Lets take the absolute value brackets away for a sec. Add 3 to both sides 9x-3+3=-12+3, simplify: 9x=-9, divide both sides by nine:9x/9=-9/9. And that means that x=-1.

Explanation for x=5/3: |9x-3|=12. Add 3. 9x-3+3=12+3. Simplify: 9x=15. Divide both sides by 9. 9x/9=15/9. Simplify: x=5/3

5 0

3 years ago

Answer question worth 25 points plz help!

Ilya [14]

Answer:

Step-by-step explanation:

6 0

3 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)= $f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........$

Where the terms in f prime $f^{1}$ (a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

$f^{1}$ (a)= $f^{1}$ (-4)=-8/( $-4)^{2}$

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+ $f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............$

$=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............$

=-2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0

1 year ago

Joshira makes and sells crafts.

Maksim231197 [3]

Answer: 6

Step-by-step explanation:

i think joshira makes 6 item in 8 hours.

i got my answer by multiplying 3/4 with 8

7 0

3 years ago

Read 2 more answers

Would you rather

Elanso [62]

Answer:

i rath r buy...

the twin-pack

sunscreen

Step-by-step explanation:

6 0

3 years ago