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3 years ago

How do I factor 8v2-8v-448=0?

Mathematics

1 answer:

Shtirlitz [24]3 years ago

3 0

Factor it should be
8(v-8)(v+7)

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If the coordinates of point A are (-3,2) and the coordinates of point B are (7,6) the x intercept of cd is

Rainbow [258]

You have to use the equation which has just slipped my mind. It say x1-y1 over x2-y2. Then you will find x. I am so sorry this equation name slipped my mind. If I remember I will let you know.

4 0

3 years ago

The back of a dog house is composed of a square and a triangle . How much wood wood is needed for the back of the dog house to t

Anastaziya [24]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Choose all the functions that give the sequence:

TEA [102]

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Further explanation:

We will put n=1,2,3,4,5 to find which functions give the given sequence

f(n) = 2n − 1

Putting values of n

$f(1)=2(1)-1=2-1=1\\f(2)=2(2)-1=4-1=3\\f(3)=2(3)-1=6-1=5$

This function doesn't generate the given sequence

f(n) = 2n + 1

Putting values of n

$f(1)=2(1)+1=2+1=3\\f(2)=2(2)+1=4+1=5\\f(3)=2(3)+1=6+1=7\\f(4)=2(4)+1=8+1=9\\f(5)=2(5)+1=10+1=11$

This function generates the given sequence.

f(n) = 2(n − 1) − 3

Putting values of n

$f(1) = 2(1 -1) -3=2(0)-3=0-3=-3\\f(2) = 2(2 -1) -3=2(1)-3=2-3=-1\\f(3) = 2(3-1) -3=2(2)-3=4-3=1$

This function doesn't generate the given sequence

f(n) = 2(n − 1) + 3

Putting values of n

$f(1) = 2(1 - 1) + 3=2(0)+3=0+3=3\\f(2) = 2(2 - 1) + 3=2(1)+3=2+3=5\\f(3) = 2(3 - 1) + 3=2(2)+3=4+3=7\\f(4) = 2(4 - 1) + 3=2(3)+3=6+3=9$

Hence, the functions that produce given sequence are:

f(n) = 2n + 1

f(n) = 2(n − 1) + 3

Keywords: Functions, Sequence

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8 0

3 years ago

Anne has a 10 3/4 pound bag of flour. Each time she bakes a batch of rolls she uses 2 1/6 pounds of flour. How many pounds of fl

LUCKY_DIMON [66]

She will have four pound left because 2 times 3 is 6 and 10 minus 6 is 4

3 0

3 years ago

Which of the following is a reasonable estimated answer to the following problem?

bulgar [2K]

$989,867 \approx 1,000,000$
$999 \approx 1000$

$\implies \frac{989,867}{999} \approx \frac{1,000,000}{1000}$
$\frac{1,000,000}{1000} = 1000$

So the answer is approximately 1000.

4 0

3 years ago

Read 2 more answers