1)volume of the pipeline
The pipeline is a cylinder, therefore;
Volume (cylinder)=πr²h
r=radius
h=height of the cylinder
diameter=6 in*(1 ft / 12 in)=0.5 ft
raius=diameter / 2=0.5 ft / 2=0.25 ft.
height=5280 ft
Volume (pipeline)=π(0.25 ft)²(5280 ft)=330π ft³≈1036.73 ft³.
2) we calculate the number of barrel
1 mile of oil in this pipeline is 330π ft³ of oil.
1 barrel of crude------------------5.61 ft³
x----------------------------------330π ft³
x=(1 barrel*330π ft³) / 5.61 ft³=184.8 barrels
3) we calculate the price.
1 barrel---------------$100
184.8 barrels---------- x
x=(184.8 barrels * $100) / 1 barrel=$18,480
Solution: ≈$18,480
Solution :
Given


Let the initial approximation is 
So by Newton's method, we get






are identical up to eight decimal places.
The approximate real root is x ≈ 1.32471795
∴ x = 1.32471795
Answer:
The value of y is -5
Step-by-step explanation:
we have
------> equation A
------> equation B
we know that
If x and y satisfy both equations, then (x,y) is the solution of the system of equations
Using a graphing tool
Remember that
The solution of the systems of equations is the intersection point both graphs
The intersection point is (2,-5)
therefore
The solution of the system of equations is the point (2,-5)
The value of y is -5