16 times 3/3 is greater than or less than or equal to 16
1 answer:
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The IQR is 42.5
Step-by-step explanation:
Interquartile range is the difference of third and first quartile.
First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.
As the number of values are odd
n=21
The median will be:
Putting n=21
The 11th term is 133
So median = 133
Now the data is divided into two halves
One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132
2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180
Q1 will be the median of first half and Q3 will be the median of 2nd half.
As now the halves contain even number of values, the medians will be the average of middle two values
<u>For First Half:</u>
98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132
<u>For Second Half:</u>
135, 135, 145, 146, 146, 156, 170 176, 180, 180
Now
<u>Interquartile Range:</u>
Hence,
The IQR is 42.5
Keywords: Median, IQR
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