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slamgirl [31]
2 years ago
12

Please help me ASAP!!!​

Mathematics
1 answer:
dalvyx [7]2 years ago
7 0

Answer:

8

Step-by-step explanation:

8 - 11 = -3 :)

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Anna [14]

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Step-by-step explanation:

a^{2} +b^{2}=c^{2} \\b^{2} =c^{2}- a^{2}\\b= \sqrt{b^{2} }

49 - 16 = 33

\sqrt{33} = 5.74

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What is the slope of the line?​
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im not very sure but i think its A or C

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What is the value of x?
Kamila [148]

Answer:

x = 3

Step-by-step explanation:

\sin \: 45 \degree =  \frac{BC}{6 \sqrt{2} }  \\  \\  \frac{1}{ \sqrt{2} } =  \frac{BC}{6 \sqrt{2} }  \\  \\ BC = 6 \\  \\  \cos \: 60 \degree =  \frac{x}{BC }  \\  \\   \frac{1}{2}  =  \frac{x}{6 }   \\  \\ x =  \frac{6}{2}  \\  \\ x = 3

7 0
3 years ago
Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
1 year ago
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