Answer:
The answer is
= Lifestyle
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Mark brainliest
Answer:
the answer is b
Explanation:
cause its the annual cash outflow
Answer:
Control limits for x_bar are between 59.076 and 60.924
Control limits for R are between 0.669 and 5.331
Explanation:
Given data:
x_bar = 60 mph
n = 10
R = 3 mph
Step 1: Factors (see table attached)
At n = 10, factors for computing control charts limits are,
A2 = Mean factor = 0.308
D3 = Lower range = 0.223
D4 = Upper range = 1.777
Step 2: Control limits for x_bar
Lower Control limit:
LCL = x_bar - A2*R = 60 - (0.308)(3) = 60 - 0.924 = 59.076
Upper Control limit:
UCL = x-bar + A2*R = 60 + (0.308)(3) = 60 + 0.924 = 60.924
The control limits for x_bar are between 59.076 and 60.924
Step 3: Control limits for R
Lower Control limit:
LCL = D3*R = 0.223(3) = 0.669
Upper Control limit:
UCL = D4*R = 1.777(3) = 5.331
The control limits for R are between 0.669 and 5.331
Hope this helps!
When airbnb customers in malibu start paying hotel taxes, this will have the potential to raise the equilibrium price in this market and, therefore, decrease efficiency. The equilibrium price refers to the market price when the quantity of goods and services supplied is equal to the demand of the goods and services. If equilibrium price rises, efficiency decreases due to the market not being equal with the supply and demand of items.
Answer:
B.
compute depreciation for a full year under straight minusline depreciation and multiply it by the fraction of the year that you held the asset.
Explanation:
Under straight-line depreciation, the asset value is spread equally throughout its useful life.
To get the depreciation of a partial year, you need to calculate the depreciation a full year first.
Divide the asset value by the number of its useful years to get depreciation value for one year. To compute partial depreciation, you need to establish the fraction of the year to be depreciated. Divide the number of months by twelve to get the fraction.
To get actual depreciation, multiply this fraction by a full year depreciation.