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3 years ago

If Julie applies 2.67 Newtons of force down onto the table, how

Physics

1 answer:

sattari [20]3 years ago

3 0

Answer:

0.6 pound.

Explanation:

From the question given above:

Julie applies 2.67 Newton (N) of force down onto the table.

Hence, we can obtain the force in pound applied by Julie on the table as follow:

Recall:

1 N = 0.225 pound

Therefore,

2.67 N = 2.67 × 0.225

2.67 N = 0.6 pound

Therefore, the force in pound applied by Julie on the table is 0.6 pound

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An airplane accelerates from rest down a runway at 9.50 m/s2 for 29.3 seconds when it

Marat540 [252]

Answer:

Explanation:

s = ½at²

s = ½(9.50)(29.3²) = 4,077.8275

s = 4080 m

when rounded to the three significant digits of the question numerals.

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3 years ago

A Red Rider bb gun uses the energy in a compressed spring to provide the kinetic energy for propelling a small pellet of mass 0.

Kay [80]

Answer:

a.6.5025 J

b.6.5025 J

Explanation:

We are given that

Mass of pellet,m=0.27 g= $0.27\times 10^{-3} kg$

1 kg=1000 g

Spring constant,k=1800 N/m

x=8.5 cm= $8.5\times 10^{-2} m$

1m=100 cm

a.Potential energy stored in the compressed spring is given by

P.E= $\frac{1}{2}kx^2$

$P.E=\frac{1}{2}(1800)(8.5\times 10^{-2})^2$

$P.E=6.5025 J$

b.By using law of conservation of energy

P.E of spring=K.E of the pellet

K.E of the pellet=6.5025 J

6 0

4 years ago

Scenario A: A 3 spring is compressed a distance of 1.0 m. Scenario B: A 6 spring is compressed a distance of 0.8 m. Scenario C:

lapo4ka [179]

The CORRECT answer is B

6 0

3 years ago

Read 2 more answers

The lightest and heaviest flying birds are the bee hummingbird of Cuba, which weighs about 1.6 grams, and the great bustard of E

VMariaS [17]

Answer:

for the birds to be able to stay vertical in flight without falling down to earth, they must produce a lift that will counteract their weight

for the small bee humming bird,

mass = 1.6 g = 1.6 x $10^{-3}$ kg

weight of the bird under acceleration due to gravity = mg

where g = acceleration due to gravity = 9.81 m/s^2

weight of the bird = 1.6 x $10^{-3}$ x 9.806 = 0.0156 ≅ 0.016 N

for this bird to maintain flight, the least lift upward, it must generate must be equal to its weight downwards, i.e

lift = weight

therefore,

lift = 0.016 N

For the bustard of Europe and Asia,

mass = 21 kg

weight of the bird under acceleration due to gravity = mg

weight of the bird = 21 x 9.806 = 205.9 N

lift = weight = 205.9 N

lift generated is proportional to the wing surface area according to the lift equation

L = Cs x p x $\frac{v}{2}$ x S

where L = lift

C = lift coefficient

p = density of air

v = relative velocity of bird and air

S = surface are of the wing.

The great bustard will have a proportionally larger wing area to hold its weight in flight

7 0

3 years ago

Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them h

Drupady [299]

Answer:

q = 7.542 x 10⁻⁷ C = 754.2 nC

Explanation:

The Coulomb's Law gives the magnitude of the force of attraction or repulsion between two charges:

F = kq₁q₂/r²

where,

F = Force of attraction or repulsion = 0.2 N

k = Coulomb's Constant = 9 x 10⁹ N m²/C²

r = distance between charges = 16 cm = 0.16 m

q₁ = magnitude of 1st charge

q₂ = magnitude of 2nd charge

Since, both charges are said to be equal here.

q₁ = q₂ = q

Therefore,

0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²

(0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²

q = √(5.88 x 10⁻¹³ C²)

q = 7.542 x 10⁻⁷ C = 754.2 nC

7 0

3 years ago