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1 year ago

15

A car is moving along a straight line op is shown below it moves from O to P in 8sec and return to p to q in 6sec. What is the a

verage velocity and the speed of the car

1 answer:

Pavel [41]1 year ago

4 0

Answer:

The answer would be A

Explanation:

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What does the churning air in the troposphere help determine

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The churning air in the troposphere helps determine the altitude of a place

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3 years ago

ASAP please!<br> need physics help on test

givi [52]

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2 years ago

Upon being struck by 240-nm photons, a metal ejects electrons with a maximum kinetic energy of 1.45 eV. What is the work functio

Bess [88]

Answer:

W = 3.73 eV

Explanation:

Given data:

wavelength of photons 240 nm

kinetic energy 1.45 eV

B y using photoelectric equation

Kinetic Energy = Photon Energy - work friction

$K.E = \frac{hc}{\lambda} -W$

$\frac{hc}{\lambda} = \frac{6.63\times 10^{-34}\times 3\times 10^8}{240\times 10^{-9}\times 1.6\times 10^{-19}} eV$

= 5.179 eV

= 5.18 eV $W = \frac{hc}{\lambda} - K.E$

= (5.18 - 1.45) eV

W = 3.73 eV

3 0

3 years ago

An "energy bar" contains 26 g of carbohydrates. For the steps and strategies involved in solving a similar problem, you may view

masha68 [24]

To solve this problem we will apply the definition of Power and Speed. In turn, we will consider that one gram of carbohydrate, according to numerous scientific studies, contributes around 17kJ of energy. Therefore, if this were true, the total energy of 26 grams would be

$E = (26)(17000) = 4.42*10^5J$

Power can be described as the amount of energy applied at a given time, that is,

$P = \frac{E}{t} \rightarrow t = \frac{E}{P}$

$t = \frac{4.42*10^5}{380}$

$t = 1.16*10^3s$

The speed is described as the distance traveled in a certain time, and its units in international system is m / s, converting and replacing we will have

$v = 5km/h(\frac{1000m}{1km})(\frac{1h}{3600s})$

$v = 1.388m/s$

Now,

$v = \frac{d}{t} \rightarrow d = vt$

The distance is,

$d = vt$

$d = (1.388)(1.16*10^3)$

$d = 1610.08m$

Therefore the distance walked is 1610.08m

7 0

3 years ago

A 12.0 g bullet was fired horizontally into a 1 kg block of wood. The bullet initially had a speed of 250 m/s. The block of wood

LuckyWell [14K]

Answer:

The rise in height of combined block/bullet from its original position is 0.45m

Explanation:

Given;

mass of bullet, m₁ = 12 g = 0.012 kg

mass of block of wood, m₂ = 1 kg

initial speed of bullet, u₁ = 250 m/s.

initial speed of block of wood, u₂ = 0

From the principle of conservation of linear momentum, calculate the final speed of the combined block/bullet system.

m₁u₁ + m₂u₂ = v(m₁+m₂)

where;

v is the final speed of the combined block/bullet system.

0.012 x 250 + 0 = v (0.012 + 1)

3 = v (1.012)

v = 3/1.012

v = 2.96 m/s

From the principle of conservation of energy, calculate the rise in height of the block/bullet combined from its original position.

¹/₂mv² = mgh

¹/₂v² = gh

¹/₂ (2.96)² = (9.8)h

4.3808 = 9.8h

h = 4.3808/9.8

h = 0.45 m

Therefore, the rise in height of combined block/bullet from its original position is 0.45m

7 0

2 years ago

Read 2 more answers