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Semmy [17]
3 years ago
9

Una rueda gira con una frecuencia de 530 rpm. Determina la velocidad angular, el periodo y la frecuencia.

Physics
1 answer:
Vlad1618 [11]3 years ago
6 0

Answer:

donde esta la bibliotekaaa

Explanation:

dfghj

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A square plate is produced by welding together four smaller square plates,
Ipatiy [6.2K]

Answer:

<h2>e</h2>

Explanation:

6 0
3 years ago
You are travelling at 60.0 mph on the Grand Central Parkway near exit 10 where it is (nearly) parallel to the Long Island Expres
Romashka-Z-Leto [24]

Answer:

a)Vr= 5 mph

b)Vr= 115 mph

Explanation:

Lets

your velocity ,u= 60 mph

velocity of truck ,v= 55 mph

When object are moving in opposite direction the relative velocity  = u +v When object are moving in opposite direction the relative velocity  = u - v

a)

Truck is moving in the same direction ,so the  relative velocity

Vr= = u - v

Vr= 60 - 55

Vr= 5 mph

b)

Truck is moving in the opposite direction ,so the  relative velocity

Vr= = u+v

Vr= 60 + 55

Vr= 115 mph

4 0
3 years ago
Which bmi score listed below is considered over weight?
valentinak56 [21]
I don't see any answer choices, but if I remember correctly, the overweight BMI score is 20-22 and up. Probably 22 and up.
5 0
4 years ago
7. How much thermal energy is absorbed when 10.0 g of ice at 0.0 degrees C changes phase to liquid water at 0.0 degrees C? The m
Nesterboy [21]

Answer:

3.34 kJ

Explanation:

FIrst of all, we need to calculate the number of moles corresponding to 10.0g of ice. This is given by

n=\frac{m }{M_m}

where

M_m = 18.02 g/mol is the molar mas

m = 10.0 g is the mass

Substituting

n=\frac{m}{M_m}=\frac{10 g}{18.02 g/mol}=0.555 mol

Now we know that the heat of fusion is

H_{fus}=6.01 kJ/mol

so the thermal energy needed to fuse the ice is

Q=n H_{fus} = (0.555 mol)(6.01 kJ/mol)=3.34 kJ

6 0
3 years ago
When two identical resistors are connected in series across ideal battery, total power dissipated by them is P. Now both are con
Art [367]

Answer:

4 P

Explanation:

V = IR

     when they are in series   R = 2 r

     when they are in parallel R = 1/2 r

         so current will increase by a factor of 4  when they are in parallel

              and power used will also increase by a factor of 4  to  4 P

Power = IV       when I now becomes 4 I     power becomes 4 P

4 0
2 years ago
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