In the case of metal, it comtains delocalised electrons which can move freely throughout the metal. when heat is applied to one end of the metal, the atoms and delocalised electrons gain more kinetic energy and move faster and they hit the neighbouring atoms more and heat is transfer theoughout the matal through conduction.
Answer : The molar heat of solution for the salt is 452.9 kJ/mole
Explanation :
First we have to calculate the heat of solution.
where,
q = heat of solution = ?
c = specific heat of water = specific heat of solution =
m = mass of solution = 107.093 g
- Mass of solution = Mass of water + Mass of salt
- Mass of solution = 100.000 g + 7.093 g = 107.093 g
= change in temperature =
Now put all the given values in the above formula, we get:
Now we have to calculate the molar heat of solution for the salt, in kJ/mol.
where,
= molar heat of solution = ?
q = heat required = 8.456 kJ
m = mass of salt = 7.093 g
Molar mass of salt = 379.984 g/mol
Therefore, the molar heat of solution for the salt is 452.9 kJ/mole
The correct answer is A. B. C. Hope this helps!!
Answer:
b) increase.
c) decrease.
d) Fringe is said to be a missing fringe when interference maxima overlap with diffraction minima.
Explanation:
a ) Young's interference is the interference phenomenon related to the light waves. Interference is the superposition of light waves . It proved the wave nature of light . Interference can be either constructive or destructive.
b) If the distance between the two slits increases, the number of fringes also increases. d sinθ = m λ. Here d is the slit width and m is the order of fringes. It shows that as d increases, m also increases.
c) Similarly, as d decreases , number of fringes decrease.
d) Fringe is said to be a missing fringe when interference maxima overlap with diffraction minima.
Answer:
Explanation:
Moment of inertia of wheel = 1/2 x mR² , m is mass and R is radius of wheel
= .5 x 9 x .4²
= .72 kg m²
Torque created on wheel by string = T x r , T is tension and r is radius of wheel .
13 x .4 = 5.2 N m
angular acceleration α = torque / moment of inertia
= 5.2 / .72
= 7.222 rad /s²
a ) final angular speed = α x t , α is angular acceleration , t is time.
= 7.222 x .72
= 5.2 rad /s
b )
θ = 1/2 α t² , θ is angle turned , t is time
= .5 x 7.222 x .72²
= 1.872 rad
average angular speed = θ / t
= 1.872 / .72
= 2.6 rad /s
c )
angle turned = 1.872 rad ( discussed above )
d )
length of string coming off
= angle rotated x radius of wheel
= 1.872 x .4
= .7488 m .
74.88 cm