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ZanzabumX [31]
4 years ago
9

What is the liquid material between the nucleus and the cell membrane?

Chemistry
1 answer:
Korolek [52]4 years ago
4 0
Cytosol,,,,,,,,,,,,,,,
You might be interested in
How many moles are in 109 grams of kf
lions [1.4K]

Answer:

Explanation:

Molar mass of KF= 39 + 19= 58g/mol

Mass of KF = 109g

Amount = mass/molar mass

Amount = 109/58

Amount = 1.9moles

4 0
3 years ago
A 581.2 mL sample of carbon dioxide was heated to 347 K.
svetlana [45]

Answer:

The temperature at 581.2 mL volume was 242.8 K.

Explanation:

Using Charle's law  

\frac {V_1}{T_1}=\frac {V_2}{T_2}

Given ,  

V₁ = 581.2 mL

V₂ = 830.5 mL

T₁ = ?

T₂ = 347 K

Using above equation as:

\frac {581.2\ mL}{T_1}=\frac {830.5\ mL}{347\ K}

T_1=\frac{581.2\times 347}{830.5}\ K=242.8\ K

<u>The temperature at 581.2 mL volume was 242.8 K.</u>

3 0
4 years ago
If 3.50 moles of sodium chloride is added to your food, how many grams is added?
Ksenya-84 [330]

Answer:

204.8g

Explanation:

The number of moles of a substance is related to its mass and molecular mass as follows:

mole (n) = mass (m) ÷ molar mass (MM)

According to this question, 3.50 moles of sodium chloride (NaCl) is added to a food.

Molar mass of NaCl = 23 + 35.5

= 58.5g/mol

Using mole = mass/molar mass

Mass = molar mass × mole

Mass = 58.5g/mol × 3.5mol

Mass = 204.75

Mass = 204.8grams.

Therefore, 204.8grams of NaCl or common salt was added to the food.

7 0
3 years ago
Which of these is an oxidation half-reaction?
Zepler [3.9K]

Answer:

E= mc sqared

Explanation:

;) lol

6 0
4 years ago
In a solution of H2SO4, rank the concentration of H2SO4, H+, SO42- from highest concentration to lowest concentration.
Softa [21]

Answer:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

Explanation:

H₂SO₄ is a strong acid, which means that most of it ionizes in aqueous solution.

Since it is a diprotic acid (two hydrogen ions) its ionization occurs in two steps:

  • H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)

  • HSO₄⁻ (aq) → H⁺(aq) + SO₄²⁻(aq)

Thus, almost all H₂SO₄ has ionized and its final concentration is almost nothing.

After the first ionization, the conentrations of H⁺(aq) and HSO₄⁻ are equal but by the second ionization more H⁺ ions are produced along with SO₄⁻.

You can show it as one step dissociation, assuming 100% dissociation (given this is a strong acid):

By the stequiometry you can build this table:

                 H₂SO₄ (aq) → 2H⁺(aq) + SO₄²⁻(aq)

Initial                A                 0              0

Change           - x               +2x          +x

Equilibrium       A - x           2x             x

As explained, A - x is very low, and 2x is twice x. Thus,

The rank of the concentrations from highest to lowest is:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

5 0
3 years ago
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