1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
telo118 [61]
3 years ago
7

How many particles are in a mole?

Chemistry
1 answer:
Free_Kalibri [48]3 years ago
7 0
Hello there.

<span>How many particles are in a mole?

Answer: </span><span>6.022</span>
You might be interested in
This is my question.............
bazaltina [42]

Answer:

-3.15 °Celsius I think.

8 0
3 years ago
Read 2 more answers
What is the correct name for the compound nh4clo4?
nevsk [136]
Ammonium perchlorate
5 0
3 years ago
What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature?
NNADVOKAT [17]

Answer:

ratio=0.996m/s

Explanation:

RMS=\sqrt{\frac{3RT}{M} }; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

V1 for 238 UF_{6}; M1=238+114=352g/mole

V1 for 235 UF_{6}; M1=238+114=352g/mole

V1=\sqrt{\frac{3RT}{352} };

V2=\sqrt{\frac{3RT}{349} };

\frac{V1}{V2}=ratio of 238UF_{6} F6 to 235UF_{6}=\sqrt{\frac{349}{352} };

\frac{V1}{V2} =0.9957m/s;

\frac{V1}{V2} =0.996m/s;

4 0
3 years ago
An industrial synthesis of urea obtains 87.5 kg of urea upon reaction of 68.2 kg of ammonia with excess carbon dioxide. Determin
dolphi86 [110]

Answer:

The theoretical yield of urea = <u>120.35kg</u>

The percent yield for the reaction = <u>72.70%</u>

Explanation:

Lets calculate -

The given reaction is -

2NH_3(aq)+CO_2 →CH_4N_2O(aq)+H_2O (l)

Molar mass of urea CH_4N_2O= 60g/mole

Moles of NH_3 = \frac{62.8kg/mole}{17g/mole} (since Moles=\frac{mass  of  substance}{mass of one mole})

                     = 4011.76 moles

Moles of CO_2 = \frac{105kg}{44g/mole}

                = \frac{105000g}{44g/mole}

                = 2386.36 moles

Theoritically , moles of NH_3 required = double the moles of CO_2

    but , 4011.76 , the limiting reagent is NH_3

Theoritical moles of urea obtained = \frac{1 mole CH_4N_2O}{2mole NH_3}\times4011.76 mole NH_3

                                                      = 2005.88mole CH_4N_2O

Mass of 2005.88 mole of CH_4N_2O =2005.88 mole \times\frac{60g CH_4N_2O}{1mole CH_4N_2O}

                                                     = 120352.8g

                                                     120352.8g\times \frac{1kg}{1000g}

                                                     = 120.35kg

Therefore , theroritical yeild of urea = 120.35kg

Now , Percent yeild = \frac{87.5kg}{120.35kg}\times100

                                 72.70%

Thus , the percent yeild for the reaction is 72.70%

8 0
3 years ago
The relative molecular mass of lead (ii) triozonitrate (v) is [pb = 108, N = 14, O = 16]
Soloha48 [4]

Answer:

need

Explanation:

points

7 0
4 years ago
Other questions:
  • How to write complete ionic and net ionic equations?
    12·1 answer
  • Which one of the following solutions will have the greatest concentration of hydroxide ions?
    11·1 answer
  • How many molecules are there in 80.0g of Mg (OH)2?​
    15·2 answers
  • Determine the amount of energy (heat) in joules required to raise the temperature of 5 kg of iron from 50°C to 200°C.
    5·1 answer
  • Given the reaction at equilibrium: H2(g) + Cl2(g) ↔ 2 HCl(g) As the pressure increases at constant temperature, the mass of H2(g
    8·2 answers
  • What is the temperature of 0.52 mol of gas at a pressure 131.722kpa and a volume of 11.8l
    5·1 answer
  • Why silver crystals should be dissolved in distilled water?​
    13·1 answer
  • A small piece of Cr metal reacts with dilute HNO3 to form H2 (g), which is collected over water at 18 C in a large flask. The to
    12·2 answers
  • Standard temperature and pressure (STP), in the context of gases, refers to a) 298.15 K and 1 atm b) 273.15 K and 1 atm c) 298.1
    12·1 answer
  • 1. I am a vertebrate
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!