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Sergio039 [100]
3 years ago
10

Balance the chemical equation. Based on the equation, how many grams of bromine are produced by the complete reaction of 11 gram

s of potassium bromide? Use the periodic table to get the weights of the elements. Carry out your calcuation in the same way as you did in parts A, B, and C. That is, begin by converting grams of KBr to moles of KBr, then use the mole ratio of KBr to Br2.
Chemistry
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

Explanation:

The balanced chemical equation is Cl2 + 2KBr → 2KCl + Br2. The amount of bromine is calculated as follows:

11.0 g KBr (1mol KBr/119.002g KBr * 1mol Br2/2mol KBr * 159.808g Br2/1mol Br2= 7.39 g Br2.)

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Answer: The energy of an electron depends on its location with respect to the nucleus of an atom. The higher the energy of an electron in an atom, the farther is its most probable location from the nucleus.

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How do i convert decimals into scientific notation
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5 0
2 years ago
Calculate the concentration of each species in a 0.240 m c6h5nh3cl solution.
amm1812
The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+ 
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5 

=2.6 x 10^-5 = x^2 / 0.240-x 
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pH = 2.60 is the concentration
8 0
2 years ago
What is the sodium ion concentration in a solution that is 0.175 M in sodium carbonate?
murzikaleks [220]
Na2CO3 Na= 23*2=46 C=12 O=16*3=48. Na2CO3=106. 46/106*0.175=0=403
7 0
2 years ago
300 grams of a compound which contains only carbon, hydrogen and oxygen is analyzed and found to contain the exact same percenta
ser-zykov [4K]

The empirical formula of the compound is C₄H₅O₃.

<u>Explanation</u>:

If hydrogen % = 5.98823, the Sum of C+O = 94.01177% or 47.005885% each

The original mass of 300 g is not important

C = 47.005885 / 12.011 = 3.913569

H = 5.98823 / 1.008 = 5.94070  

O = 47.005885 / 15.999 = 2.93805  

Divide by the smallest number:      

C =1.33  

H = 2.022

O = 1

Multiply through by 3

C = 4

H =6

O = 3

The empirical formula of a compound = C₄H₆O₃

Do not be confused by the 300 g. It is totally irrelevant to the question because you are dealing with % amounts. It would only have been of importance if you were given some mass values.

4 0
3 years ago
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