The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:
Then, the combination of the frequency of the tuning fork and the open orang pipe is:
These combinations of frequency produce 4 beats per sound.
i.e.
When it is altered, the beats first diminish and increase again by 4.
i.e.
If we equate both equations (1) and (2) together, we have:
However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
- when the temperature of the pipe = unknown ???
- the temperature of the open orang pipe = 15
∴
By squaring both sides, we have:
T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
Learn more about wave frequency here:
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15/70 =3/14 miles per minute = 0.21 miles a minute. One mile in about 5 minutes. Sarah is shifting, I think (faster than me)
Answer:
n = 1.56
Explanation:
The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship
n₁ sin θ₁ = n₂ sin θ₂
n1 = n2 / sin θ₁
For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle
Let's use trigonometry to find angle
tan θ = y / x
θ = tan⁻¹ 7.2 / 8.6
θ = 39.94º
n₁ = 1 / sin 39.94
n = 1.56
This is the refractive index of the liquid
Answer:
a) 1/4 what it is now
Explanation:
As we know that force of gravitation between two planets at some distance "r" from each other is given as
now since we know that if the distance between Earth and Sun is changed
So the force of gravity will be given as
now we know that the distance between sun and earth is changed to twice the initial distance between them
so we have
so new gravitational force between sun and earth is given as
I do not know of the following in your class, but the wall is still and non-moving, while the hockey player is pushing off of it, as stated. So, this is not inertia, for a fact, because the wall is not moving towards the hockey player.
