All categories

4 years ago

(01.06 LC)

Physics

1 answer:

Marta_Voda [28]4 years ago

4 0

Answer:

Equilibrium is reached when demand equals supply.

Explanation:

Demand is the amount that consumers want and can buy of a certain product or service in a specific period of time and at a certain price. On the other hand, the supply is the amount that producers want and can sell of a certain product or service in a specific period of time and at a certain price.

In market equilibrium, the quantity demanded of the product or service equals the quantity supplied, so the price also equals. In other words, when market equilibrium is reached, demand and supply are the same, with their corresponding equilibrium price and quantity.

Two situations can occur:

When the quantity demanded is greater than the quantity supplied, the market is in a situation of excess demand.

On the other hand, it may happen that the price at which the products are being offered is greater than the equilibrium price and the quantity supplied is greater than the quantity demanded. Then there is an excess supply.

Equilibrium is reached when demand equals supply.

You might be interested in

Al colocar un objeto delante de una lente convergente se genera una imagen real invertida y de doble tamaño, sabiendo que dicha

alexira [117]

Answer:

30 cm

Explanation:

To solve this problem, we use the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f is the focal length of the lens

p is the distance of the object from the lens

q is the distance of the image from the lens

In this problem, we know that

q = -30 cm is the distance of the image from the lens; it is negative because the image is formed in front of the lens, so it is a virtual image

We also know that the size of the image is twice that of the object, so the magnification is 2:

$M=-\frac{q}{p}=2$

where M is the magnification of the lens. Solving this equation for p,

$p=-\frac{q}{2}=-\frac{-30}{2}=15 cm$

So, the distance of the object from the lens is 15 cm.

Now we can finally solve the lens equation to find f, the focal length:

$\frac{1}{f}=\frac{1}{15}+\frac{1}{-30}=\frac{1}{30}\\\rightarrow f=30 cm$

5 0

4 years ago

The manufacturer of a 6 V dry-cell flashlight battery says that the battery will deliver 15 mA for 64 continuous hours. During t

Misha Larkins [42]

Answer:

E =17,280 J

Explanation:

Since the voltage drops linearly from 6V to 4V, the average is 5V. The energy delivered is .

V is the average of initial and fianl voltage

A is the current passing

t is the time in which current is passed

E=V*A*t = 5*0.015*(64*3600) = 17,280 J

6 0

3 years ago

If the density of the fuel is 0.821 g/ml, what mass of fuel has the airplane taken on?

bija089 [108]

Mass of fuel has the airplane took on = 167.89 kg

$\boxed{\boxed{\bold{Further~explanation}}}$

Density is a quantity derived from the mass and volume

density is the ratio of mass per unit volume

With the same mass, the volume of objects that have a high density will be smaller than objects with a smaller type of mass

The unit of density can be expressed in g / cm3 or kg / m3

Density formula:

$\large{\boxed{\bold{\rho~=~\frac{m}{V} }}}$

ρ = density

m = mass

v = volume

A common example is the water density of 1 gr / cm3

If we look at fuel capacity data such as Airbus which has a maximum capacity of 204, 5 liters then the mass of fuel it carries is

ρ = 0.821 gr / ml = 0.821 kg / l

mass = ρ . V

mass = 0.821 kg / l . 204.5 liters

mass = 167.89 kg

So the mass of fuel carried by aircraft is 167.89 kg

$\boxed{\boxed{\bold{Learn~more}}}$

density and molarity of the solution brainly.com/question/8151398

the percent of acetic acid in the vinegar brainly.com/question/3001349

the mass percent brainly.com/question/5142462

the mass of the fuel in kilograms brainly.com/question/8312085

the relative density of the fuel

brainly.com/question/10889330

Keywords: density, mass, volume, aircraft, fuel, derivative quantities

7 0

3 years ago

Read 2 more answers

A 1,000 kg car travels at 15m/s

adell [148]

Answer:

not complete question

but also.:

5 0

3 years ago

Suppose the moon were held in its orbit not by gravity but by the tension in a massless cable. You are given that the period of

Ksenya-84 [330]

Answer:

Tension in the cable = 200.655 × 10^(18) N

Explanation:

The tension in the cable will be the force on the string which is caused by when it holds against the centripetal acceleration.

Now, the formula for centripetal acceleration is given by;

a = v²/R

Now, let's find the velocity.

The circumference is 2πR

We are given that R = 3.85 x 10^(8) m

So, Circumference = 2 × π × 3.85 x 10^(8) = 24.19 × 10^(8) m

We are told the period of the moon orbit is 27.3 days

Distance travelled per day = Circumference/ period

Distance travelled per day = (24.19 × 10^(8))/27.3 = 88608058.608 m/day

Now, a day has 24 hours = 24 × 60 × 60 = 86400 seconds

Thus,

Distance travelled per seconds =

88608058.608/86400 = 1025.556 m/sec

So, from a_c = v²/r,

a_c = 1025.556²/3.85x10^8

a_c = 0.00273 m/s²

Now, Force = Mass x Acceleration = ma

We are given mass = 7.35 x 10^(22) kg

Plugging in the relevant values, we have;

F = 0.00273 x 7.35 x 10^(22)

F = 200.655 × 10^(18) N

5 0

3 years ago