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Rzqust [24]
3 years ago
13

A 50,0 g silver spoon at 20.0°C is placed in a cup of coffee at

Physics
1 answer:
My name is Ann [436]3 years ago
8 0

The heat capacity of the silver spoon at the given temperature difference is 817.65 J.

<h3>Heat capacity of the silver spoon</h3>

The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;

Q = mcΔθ

where;

  • m is mass of the spoon
  • c is specific heat capacity of silver = 0.237 J/g⁰C
  • Δθ is change in temperature

Q = 50 x 0.237 x (89 - 20)

Q = 817.65 J

Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.

Learn more about heat capacity here: brainly.com/question/16559442

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Describe different types of motion with examples. (4)
Illusion [34]

Answer:

a)

there r two types of motion, uniform and non-uniform

uniform means equal distance travelled at equal intervals of time

and non-uniform is exactly the opposite.

b)

quantities which can be represented by magnitude along r called scalar quantities such as speed.

quantities which need magnitude along with direction r called vector quantities such as velocity.

c)

velocity=10m/s

acceleration = u-v/s i.e initial final velocity - initial velocity upon time

acceleration= 0.2m/s sq

time= 30s

10 = displacement/time

10 = x/30

10 = 300

Answer is 300 meters - distance/displacement.

8 0
3 years ago
Read 2 more answers
Please really need help with this one
sergij07 [2.7K]
Well... question 7. kinetic energy is "energy in which a body processes while being in motion" :)
4 0
4 years ago
calculate the period of a wave whose frequency is 5 Hertz and whose wavelength is one centimeter give your answer in a decimal f
olga2289 [7]
The period of the wave is the reciprocal of its frequency.

       1 / (5 per second)  =  0.2 second .

The wavelength is irrelevant to the period.  But since you
gave it to us, we can also calculate the speed of the wave.

Wave speed = (frequency) x (wavelength)

                   = (5 per second) x (1cm)  =  5 cm per second
4 0
4 years ago
A 5 kg fish swimming at 1 m/s swallows an absentminded 500 g fish swimming toward it at a veloc- ity that brings both fish to a
morpeh [17]

Answer:

v = 10 m/s

Explanation:

given,

Mass of large fish, M = 5 Kg

speed of swimming, v' = 1 m/s

mass of small fish, m = 500 g = 0.5 Kg

speed of the fish = v

using conservation of momentum

m v + M v' = M u' + m u

final speed of both the speed is zero.

- 0.5 x v + 5 x 1  = 0

negative sign is used because small fish is moving in opposite direction.

now,

0.5 v = 5

v = 10 m/s

hence, the speed of the small fish is equal to 10 m/s.

8 0
3 years ago
Some hydrogen gas is enclosed within a chamber being held at 200^\ { C} with a volume of 0.025 \rm m^3. The chamber is fitted wi
vlada-n [284]

Answer:

The final volume is 0.039 m^3

Explanation:

<u>Data:</u>

Initial temperature: T1=200C

Final temperature: T2=200C

Initial pressure: P1=1.50 \times10^6 Pa

Final pressure: P2=0.950 \times10^6 Pa

Initial volume: V1=0.025m^{3}

Final volume: V2=?

Assuming hydrogen gas as a perfect gas it satisfies the perfect gas equation:

\frac{PV}{T}=nR (1)

With P the pressure, V the volume, T the temperature, R the perfect gas constant and n the number of moles. If no gas escapes the number of moles of the gas remain constant so the right side of equation (1) is a constant, that allows to equate:

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

Subscript 2 referring to final state and 1 to initial state.

solving for V2:

V_{2}=\frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}}=\frac{(1.50 \times10^6)(0.025)(200)}{(200)(0.950 \times10^6)}

V_{2}=0.039 m^3

3 0
4 years ago
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