![y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\ y''(0)=20\cdot0^3=0](https://tex.z-dn.net/?f=y%3Dx%5E5-3%5C%5C%20y%27%3D5x%5E4%5C%5C%5C%5C%205x%5E4%3D0%5C%5C%20x%3D0%5C%5C%200%5Cin%20%5B-2%2C1%5D%5C%5C%5C%5C%20y%27%27%3D20x%5E3%5C%5C%5C%5C%0Ay%27%27%280%29%3D20%5Ccdot0%5E3%3D0)
The value of the second derivative for
is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of
is always positive for
. That means at
there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval
![[-2,1]](https://tex.z-dn.net/?f=%5B-2%2C1%5D)
.
The function
is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.
Answer:
-3b³ - 5b² + 10b
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define Expression</u>
(10b + 7b² - 6b³) - (12b² - 3b³)
<u>Step 2: Simplify</u>
- Distribute negative: 10b + 7b² - 6b³ - 12b² + 3b³
- Combine like terms (b³): -3b³ + 10b + 7b² - 12b²
- Combine like terms (b²): -3b³ - 5b² + 10b
Answer:
$5.00
Step-by-step explanation:
It doesn't say his money has changed so it is still $5.00
Answer:
A. drag it to the right
b. drag it to the left
Step-by-step explanation:
