A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
sorry i need more points
Step-by-step explanation:
Answer:
yes
Step-by-step explanation:
euhm ... did u just asked if a figure with h=9inches and b=12inches is rectangular???
Does it matter what the diagonals are etc?
if the frame has angles of 90° and it has two different lengths then it has to be rectangular. The sides of a square would have the same lengths.
Postulate, because we just assume that it is a true fact.
Answer:
b
Step-by-step explanation:
