If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams
The half life in years = 24100
Consider the quantity of the radio active isotope remaining
y = 
When t = 1000 the y = 1.2
y = C/2 when t = 1599
Substitute the values in the equation
C/2 = 
Cancel the C in both side
1/2 = 
Here we have to apply ln to eliminate the e terms
ln (1/2) = 24100k
k = ln(1/2) / 24100
k = -2.87× 10^-5
To find the initial value we have to substitute the value of k and y in the equation
1.2 = Ce^{1000 × -2.87× 10^-5}
C = 1.2 / e^(-0.0287)
C = 2.16 gram
Hence, the initial quantity of the radioactive isotope is 2.16 gram
Learn more about half life here
brainly.com/question/4318844
#SPJ4
Answer:
What's the difference between a number track and a number line? A number track is a sequence of numbers, each inside its own square. ... Whereas, a number line is where the numbers are attached to markers on a line. This method of addition / subtraction comes later.
Answer:
16ft
Step-by-step explanation:
use pythagreom thereom
12^2+b^2=20^2 solve
144+b^2=400
b^2= 256 square it
b= 16
*triple phytagoras*
first triangle h = second triangle h = 24 in
x = 7 (triple phytagoras)
Answer:
The surface area is 
Step-by-step explanation:
we know that
The surface area of a square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces.
so
![SA=b^{2}+4[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
we have
substitute the values
![SA=0.4^{2}+4[\frac{1}{2}(0.4)(0.6)]=0.64\ m^{2}](https://tex.z-dn.net/?f=SA%3D0.4%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%280.4%29%280.6%29%5D%3D0.64%5C%20m%5E%7B2%7D)
