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Lostsunrise [7]
3 years ago
8

If someone rented a bike that cost $20 + $7 per hour and they paid $76, then how much hours did they rent the bike for?

Mathematics
2 answers:
never [62]3 years ago
7 0
$20 + $7 = $27

$20 + $7 = $54

$20 + $7 = $81

81 - 7 = 74

74 - 71 = 3.

The estimated answer is about 3 hours and 20 minutes

AfilCa [17]3 years ago
3 0
20+7h=76
7h=56
h=8. As a result, they rented tr bike for 8 hours. Hope it help!
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What is the answer to (x+8)(x+8)
Inessa05 [86]
(x+8)(x+8)=64x because 8*8=64 and the x is one so which means it eqaled to 1 so the answer would be 64x
8 0
3 years ago
Evaluate the following limit, if it exists : limx→0 (12xe^x−12x) / (cos(5x)−1)
Amanda [17]

Answer:

\lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}

Step-by-step explanation:

Notice that \lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=\frac{12(0)e^{0}-12(0)}{cos(5(0))-1}=\frac{0}{0}, which is in indeterminate form, so we must use L'Hôpital's rule which states that \lim_{x \to c} \frac{f(x)}{g(x)}=\lim_{x \to c} \frac{f'(x)}{g'(x)}. Basically, we keep differentiating the numerator and denominator until we can plug the limit in without having any discontinuities:

\frac{12xe^x-12x}{cos(5x)-1}\\\\\frac{12xe^x+12e^x-12}{-5sin(5x)}\\ \\\frac{12xe^x+12e^x+12e^x}{-25cos(5x)}

Now, plug in the limit and evaluate:

\frac{12(0)e^{0}+12e^{0}+12e^{0}}{-25cos(5(0))}\\ \\\frac{12+12}{-25cos(0)}\\ \\\frac{24}{-25}\\ \\-\frac{24}{25}

Thus, \lim_{x \to 0} \frac{12xe^x-12x}{cos(5x)-1}=-\frac{24}{25}

3 0
2 years ago
Help please i need help
Artist 52 [7]

Answer: 21

Step-by-step explanation: hope this helps :)

7 0
3 years ago
-49 + (-46) =<br> -50 + 27 =
vesna_86 [32]
1. -96 just simply add those two and it will be -96

2. -50 +27=  change the signs- -50- -27= -23 just subtract

Hope this helps!

3 0
2 years ago
Express the percent as a decimal.<br> 154%
tresset_1 [31]

Answer:

1.54 as a decimal

154 divided by 100 to get 1.54

Step-by-step explanation:

3 0
3 years ago
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