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hram777 [196]
3 years ago
11

What's Pi to 12 decimal places

Mathematics
1 answer:
Margarita [4]3 years ago
8 0
3.14159265358979

That's more than 12 decimal places but it's all I remember off-by-heart.
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Easy algebra! Just need help with this one
Alexxandr [17]
The answer is B (9,6) (12,8)
6 0
3 years ago
Find the surface area of the pyramid shown to the nearest whole number. The base is a regular hexagon.
Fiesta28 [93]
The surface area of the pyramid will be given as follows:
Area of triangles:
A=1/2×base×height
A=1/2×12×18
A=108 m²
Area of 6 triangles is given by:
A=108×6=648 m²

Area of the hexagon:
A=6×1/2×12×6√3
A=374.123m²

Total surface area:
SA=648+374.123
SA=1022.123 m²~1022 m²

Answer: C] 1022 m²

8 0
3 years ago
Evaluate Y=3x-5 when x=6
Harman [31]
7 + (-3x^2) for x = 0 7 + [-3(0)^2]; = 7 + -3(0); = 7 - 0; = 7
6 0
3 years ago
A spinner has equal regions numbered 1 through 20. What is the probability that the spinner will stop on an odd number or a mult
klio [65]

Answer:

<em>Probability that the spinner will stop on an odd number or a multiple of 5 is </em><em>0.6</em>

Step-by-step explanation:

Probability = \frac{Required outcomes}{Total possible outcomes}

We are given the equal regions numbered from 1 through 20 which means that our total possible outcomes are 20

<em>Total possible outcomes: 20</em>


<em>Outcomes that spinner will stop on an odd number, n(Odd): 10</em>

1, 3, 5, 7, 9, 11, 13, 15, 17, 19

Probability of spinner stoping on Odd number:

P(Odd) = \frac{n(Odd)}{Total} = \frac{10}{20} = \frac{1}{2} = 0.5


Outcomes that spinner will stop on a multiple of 5, n(5): 4

5, 10, 15, 20

Probability of spinner stoping on multiple of 5:

P(5) = \frac{n(5)}{Total} = \frac{4}{20} = \frac{1}{5} = 0.2

Odd numbers which are a multiple of 5 are: 5 and 15

So,

P(Odd and 5) = \frac{2}{20}=\frac{1}{10}=0.1

Thus Probability of spinner stopping at odd number or a multiple of 5 becomes:

P(Odd or 5) = P(Odd) + P(5) - P(Odd and 5) = 0.5 + 0.2 - 0.1 = 0.6

7 0
4 years ago
A can holds 4 golf balls. The diameter of each golf ball is 5 cm. What is the volume of the empty space inside the can?
forsale [732]

Answer:

Volume of the empty space in the can  is 327.05  cm^3

Step-by-step explanation:

Given:

Number of golf ball the can holds = 4

Diameter of the golf ball = 5 cm

To Find:

Volume of the empty space in the can = ?

Solution:

Step 1:  Finding the volume of one golf ball

Ball is shape of the sphere

So lets use the volume of the sphere formula

Volume of the  golf ball = \frac{4}{3}\pi r^3

Radius =\frac{5}{2} = 2.5 cm

Substituting the values

Volume of the  golf ball  

=\frac{4}{3} \pi \times(2.5)^3

=\frac{4}{3} \pi \times (15.625)

= \frac{4}{3} \times 49.06

= \frac{196.24}{3}

= 65.41

Step 2:  Finding the volume of empty space of the can

volume of empty space of the can =  volume of 5 golf ball

= 5 X 65.41

= 327.05

7 0
4 years ago
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