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3 years ago

What is thr sum of the numbers in the first column

Mathematics

2 answers:

11111nata11111 [884]3 years ago

8 0

The sum of the summers in the first column are 57

muminat3 years ago

3 0

The answer would be 57

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Which expressions are equivalent to -56z + 28.

NeX [460]

Answer:

B and C

Step-by-step explanation:

(-7)•8z = -56z

(-4)•(-7)=28

and

40•(-1.4)= -56z

40•0.7= 28

5 0

2 years ago

Rewrite in simplest terms: 5(0.9m+0.5)-3(0.4m+0.7)

hram777 [196]

Answer:

3.3m+1.4

Step-by-step explanation:

Multiply 5 and 0.9m

Multiply 5 and 0.5

5 times 0.9m is 4.5m

5 times 0.5 is 2.5

Multiply -3 and 0.4m

Multiply -3 and 0.7

-3 times 0.4m is -1.2m

-3 times -.7 is -2.1

4.5m+ 2.5 -1.2m-2.1

Which is 3.3m+1.4

Hope this helps!

3 0

2 years ago

Substitution for {2x-3y=11 and -x + 2y = -6

Svetradugi [14.3K]

Step-by-step explanation:

-x+2y=-6

x-2y=6

x=2y+6

substitute in 2x-3y=11 gives us 2(2y+6)-3y=11

4y+12-3y=11

y=-1

-x+2(-1)=-6

-x=-4

x=4

7 0

3 years ago

Write an equation (any form) for the quadratic graphed below. Y=

Licemer1 [7]

Answer:

y = -2x^2 - 4x - 1

Step-by-step explanation:

We can see that the graph passes through (-2, -1), (-1, 1) and (0, -1).

Let's solve

ax^2 + bx + c = y

a(-2)^2 + b(-2) + c = -1

4a - 2b + c = -1

a(-1)^2 + b(-1) + c = 1

a - b + c = 1

a0^2 + b0 + c = -1

c = -1

we got c = -1 so we input it into the other 2

4a - 2b - 1 = -1

4a - 2b = 0

2a - b = 0

2a = b

a - b - 1 = 1

a - b = 2

a = b + 2

Let's input b = 2a

a = 2a + 2

-a = 2

a = -2

b = 2a = 2*(-2) = -4

c = -1

y = -2x^2 - 4x - 1

4 0

3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

4 0

3 years ago

What is thr sum of the numbers in the first column ​

What is thr sum of the numbers in the first column