The values In the table represent a linear function. How does the value of y change in relation to a change in the value of x?

A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec

natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

50 parts means that $N = 50$

4 defective means that $k = 4$

10 are chosen, which means that $n = 10$

What is the probability this shipment passes inspection?

Probability that none is defective, so:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968$

0.3968 = 39.68% probability this shipment passes inspection.

6 0

2 years ago

The first metacarpal bone is located in the wrist. The scatterplot below shows the relationship between the length of the first

gulaghasi [49]

The question is incomplete so I am writing the complete question below and attaching the scatter plot as well.

The first metacarpal bone is located in the wrist. The scatterplot below shows the relationship between the length of the first metacarpal bone and height for 9 people. The line of best fit is also shown

How many of the nine people have an actual height that differs by more than 3 centimeters from the height predicted by the line of best fit?

Answer:

4 people have an actual height that differs by more than 3 cm from the height predicted by the line of best fit.

Step-by-step explanation:

The question is asking us to identify which people have a height that is more than 3 cm greater or more than 3 cm less then the height predicted by the line of best fit. Hence, we need to look at the outliers of the line if best fit i.e. the points which do not lie on the line. We need to select the points that differ by 3 or more cm.

So, we can see that the first person (4 cm) has an actual height of 157 cm but the line of best fit shows the height is 161.5. So, there is a difference of more than 3 cm (161.5 - 157 = 4.5).

The second outlier at 4.3 has an actual height of 175 cm but the line of best fit shows a height of 167 cm. There is a difference of 8 cm hence this person also has an actual height which differs by more than 3 cm from the line of best fit.

At 4.8 cm metacarpal bone height, the person's actual height is 172 cm but the graph shows a height of 176 cm hence this person also has an actual height which differs by more than 3 cm from the line of best fit.

At 4.9 cm on the x-axis, the person has an actual height of 183 cm but the line of best fit shows 178 cm so this person also has an actual height which differs by more than 3 cm from the line of best fit.

So, in total there are 4 people out of 9 whose heights differ by more than 3 cm from the line of best fit.

6 0

2 years ago

Draw a rhombus that is not a square. Label the lengths of its sides and its height so it represents a rhombus with an area of 20

Tcecarenko [31]

Answer:

/\

$\sqrt{20}$ / \ $\sqrt{20}$

/ \

\ /

$\sqrt{20}$ \ / $\sqrt{20}$

\/

Step-by-step explanation:

i hope this is right it took me 30 min for the ascii

6 0

3 years ago

Let the random variable Q represent the number of students who go to a certain teacher's office hour each day. The standard devi

postnew [5]

Answer: А. On average, the number of students going to an office hour varies from the mean by about 2.2 students

Step-by-step explanation:

The standard deviation is a measure of spread, which gives how values deviate from the average or mean value of a particular distribution. Hence, the standard deviation is usually defined about the average value of a distribution.

Therefore, for a certain random variable representing the number of student who visits office hours, the standard deviation will be defined about the average or mean value of the random variable Q.

Thus, stated as ; number of students going to an office hour varies from the mean by 2.2 on average.

4 0

2 years ago

Read 2 more answers

If 6 out of 30 people over the age of 100 are male, how many are female

RoseWind [281]

The remainder of the thirty once you remove the 6 who are male.
30-6=24..

5 0

3 years ago