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amm1812
2 years ago
10

The values In the table represent a linear function. How does the value of y change in relation to a change in the value of x?

Mathematics
1 answer:
SVEN [57.7K]2 years ago
7 0

Answer:

The answer is B for every change in x by 2, y changes by 4

Step-by-step explanation:

Let me know if this helps :)

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What is the value of x in the equation 2(x+3) = 4(x-1)?<br> own
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Step-by-step explanation:

Solving

2x + 6 = 4x - 4

Bringing like terms on one side

6 + 4 = 4x - 2x

10 = 2x

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5 = x

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3 years ago
A number is not an interger.What type of number can it be?
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A cable car begins its trip by moving up a hill. As it moves up, it gains elevation at a constant rate of 50 feet/minute until i
asambeis [7]

Answer:

he cable car's elevation will be 750 feet after 15 minutes

Step-by-step explanation:

Given:

elevation, e =2,000 feet

rate, I = 50 feet/minute

The equation that models the car's elevation, e, after t minutes is e = |t

The cable car's elevation will be 750 feet after how many minutes?

since, e = It

for 2,000 feet = 50 feet/minute  * t

t = 2000/50 =40minutes

using the same constant rate, I for 750ft, T =

since, e = It

for 750 feet = 50 feet/minute  * t

t = 750/50 =15minutes

3 0
3 years ago
X–2 1/2=6 3/4. X=?<br><br> x – 3.23 = 0.77. X=?
Over [174]

Answer:

x= 105/4

x=4

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find y' by implicit differentiation √x +√y =1
AleksandrR [38]
Differentiate both sides with respect to x

\frac{d}{dx}(x^{\frac{1}{2}} + y^{\frac{1}{2}}) = \frac{d}{dx}(1)\\\\ \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0\\\\\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}\\\\\frac{1}{2\sqrt{y}}\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \\\\\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \times 2\sqrt{y}\\\\\frac{dy}{dx} = -\frac{\sqrt{y}}{\sqrt{x}} \\\\\boxed{\bf{y'= -\frac{\sqrt{y}}{\sqrt{x}}}}
5 0
3 years ago
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